deserialization

How to deserialize Avro messages from Kafka in Flink (Scala)?

强颜欢笑 提交于 2019-12-23 04:54:28
问题 I'm reading messages from Kafka into Flink Shell (Scala), as follows : scala> val stream = senv.addSource(new FlinkKafkaConsumer011[String]("topic", new SimpleStringSchema(), properties)).print() warning: there was one deprecation warning; re-run with -deprecation for details stream: org.apache.flink.streaming.api.datastream.DataStreamSink[String] = org.apache.flink.streaming.api.datastream.DataStreamSink@71de1091 Here, I'm using the SimpleStringSchema() as the deserializer, but actually the

Newtonsoft escaped JSON string unable to deseralize to an object

浪子不回头ぞ 提交于 2019-12-23 02:03:04
问题 Question background: I am receiving a JSON response via a HttpResponseMessage, as shown: var jsonString= response.Content.ReadAsStringAsync().Result; This is giving me the following simple escaped JSON string result: "\"{\\\"A\\\":\\\"B\\\"}\"" The problem: I am using Newtonsoft to try and deserialize this to a model: SimpleModel simpleModel= JsonConvert.DeserializeObject<SimpleModel>(jsonString); The Class model of SimpleModel : public class SimpleModel { public string A { set; get; } } The

How I deserialize a dynamic json property with RestSharp in C#?

喜你入骨 提交于 2019-12-22 21:37:12
问题 I have a web service (I can't edit) with this structure: /users { "response" : { "users": [{"name": "John"},{"name": "Jack"}] }, "page" : { "current":1, "total":1} } /pets { "response" : { "pets": [{"name": "Fido"},{"name": "Tweety"}] }, "page" : { "current":1, "total":1} } As you can see the property name in the "response" property changes. How can deserialize a generic response with RestSharp? I don't want to write a Response class for every resource. I have written the following generic

How I deserialize a dynamic json property with RestSharp in C#?

南笙酒味 提交于 2019-12-22 21:36:59
问题 I have a web service (I can't edit) with this structure: /users { "response" : { "users": [{"name": "John"},{"name": "Jack"}] }, "page" : { "current":1, "total":1} } /pets { "response" : { "pets": [{"name": "Fido"},{"name": "Tweety"}] }, "page" : { "current":1, "total":1} } As you can see the property name in the "response" property changes. How can deserialize a generic response with RestSharp? I don't want to write a Response class for every resource. I have written the following generic

XStream won't call readObject()

安稳与你 提交于 2019-12-22 18:44:11
问题 I have code that is modeled as such: class A { private transient Foo foo = new Foo(); private void readObject(ObjectInputStream in) throws IOException, ClassNotFoundException { in.defaultReadObject(); foo = new Foo(); } } class B extends A {} I added readObject() to A so that during deserialization, the transient foo will be initialized. However, I stuck breakpoints in my code and could see that XStream is not calling readObject() at all. I also tried sticking readObject() in class B that

How to deserialize child object into list of parent (ex, List<Parent>) based on values of xml nodes?

≯℡__Kan透↙ 提交于 2019-12-22 18:32:30
问题 I have one XML file called VehicleInfo. I want to deserialize VehicleInfo in List of Vehicle. Now I have one base class called Vehicle and three derived class named as Car, Bike, Truck. How to deserialize specific object of vehicle based on value of Vehicle node in xml. (ex. if node value is Car than object of car should be stored in List of vehicle) <Vehicles> <Vehicle>Car</Vehicle> <Vehicle>Bike</Vehicle> <Vehicle>Truck</Vehicle> </Vehicles> For example, VehicleList class : public class

No DataSerializeFactory registered for namespace

放肆的年华 提交于 2019-12-22 18:29:18
问题 I tried it in HZ 3.4 and 3.4.1 but with the same output I`m trying to import dummy data to my Hazelcast cluster, with following function HazelcastInstance cluster = HazelcastClient.newHazelcastClient(this.conf); Map<String, Customer> mapCustomers = cluster.getMap("customers"); System.out.println(mapCustomers.size()); System.out.println("hello world"); for (int customerID = 0; customerID < 2000; customerID++) { Customer p = new Customer(); mapCustomers.put(Integer.toString(customerID), p);

Unity Deserializing from server [duplicate]

不想你离开。 提交于 2019-12-22 10:27:12
问题 This question already has answers here : Serialize and Deserialize Json and Json Array in Unity (7 answers) Closed 2 years ago . I have been trying for a couple hours to deserialize info from my server for our high score system. However I am getting an error: ArgumentException: JSON must represent an object type. This is how I am deserializing ( scores is of type Scores): public void Deserialize() { Debug.Log("From Server is ::::: -----> " + FromServer); scores = JsonUtility.FromJson<Scores>

How to update WPF UI at deserialization of “settings” object

久未见 提交于 2019-12-22 10:15:47
问题 My goal is to do this: User selects settings file, settings are read and the UI is updated correspondingly. Saving should also be possible obviously. My program is currently not WPF/XAML and doing this now would mean a lot of repetition and added work when new settings are required. So someone told me WPF/XAML was the way to go, I looked into it and liked it but I'm still not sure how to do what I want. The advantage of WPF/XAML is of course data bindings, but if I want to read a whole

Complex XML deserialization

时光毁灭记忆、已成空白 提交于 2019-12-22 09:59:20
问题 I'm trying to deserialize a complex XML file. i have my main class structured so it gets all of the info in the first child nodes, I even have it so that i can obtain the ClientName which is two layers deep. However, anything beyond that does not seem to work. I get a List item with a count of 1 but no information is inside the list. My OrderTaxes and OrderTransactions lists come back with a Count = 1 but all of the fields are null. I'm positive it is a problem with my class structure and any