definition

In the following statement the val f is defined as a lambda that references itself (it is recursive): val f: Int => Int = (a: Int) => if (a > 10) 3 else f(a + 1) + 1 // just some simple function I've tried it in the REPL, and it compiles and executes correctly. According to the specification, this seems like an instance of illegal forward referencing: In a statement sequence s[1]...s[n] making up a block, if a simple name in s[i] refers to an entity defined by s[j] where j >= i , then for all s[k] between and including s[i] and s[j] , s[k] cannot be a variable definition. If s[k] is a value

In order to do runtime transformations in Babel you need to require and use babel-core/register . I have no idea what register means in this sense, i.e. the actual definition. The page isn't very helpful. What does this actually mean? Jason Ashley ok, so the purpose of babel as you know is to transpile your js current code to an understandable version of js for the given environment, tool, framework you're using. Those vary as listed here, How to use Babel with your tool of choice. In the node environment, babel does not exist as part of its core APIs, so it needs to be added as an npm package

head.h #pragma once namespace foo { int bar; int funct1(); } head.cpp #include "head.h" int foo::funct1() { return bar; } main.cpp #include <iostream> #include "head.h" int main() { foo::bar = 1; std::cout << foo::funct1() << std::endl; return 0; } Error LNK2005 "int foo::bar" (?bar@foo@@3HA) already defined in head.obj I don't understand what is going on. I tried looking for the answer but everyone's questions are so specific to their code and don't even look close to the problem that I am having. I am not including .cpp files into main. I am not redefining anything. I am literally just

I am reading up on generics in Java using the Java Language Specification, Third edition . In section " 4.6 Erasure " type erasure is defined. On the erasure of a type variable it says The erasure of a type variable (§4.4) is the erasure of its leftmost bound. This confuses me a bit regarding the distinction between type variable and type parameter since section " 4.4 Type Variables " has the definition: TypeParameter: TypeVariable TypeBound where the bound is optional. But perhaps you can identify a type variable with the type parameter it appears in since a type variable can only (?) appear

Where is struct proc_dir_entry defined in linux kernel? in /linux/proc_fs.h it is just declared as: (kernel 3.10) struct proc_dir_entry; and I think because of this I get this error: dereferencing pointer to incomplete type at this line of code though including /linux/proc_fs.h : while(strcmp (my_dir_entry->name,"tcp")) Levente Kurusa It is defined in fs/proc/internal.h . 来源： https://stackoverflow.com/questions/19334023/struct-proc-dir-entry-definition-in-kernel

I've finally remembered what to ask. I never really got what : and ? do when a variable is being defined like this: $ip = ($_SERVER['HTTP_X_FORWARDED_FOR']) ? $_SERVER['HTTP_X_FORWARDED_FOR'] : $_SERVER['REMOTE_ADDR']; As you can see there is ? and : and ( ) Could anyone give me a brief detail about why and how they are used for? John Feminella The expression looks like this: $var = (condition) ? if_true : if_false ?: is the ternary operator . If condition is true, $var will be assigned the value if_true ; otherwise it will be assigned the value if_false . In your particular case: This assigns

I am new to CUDA programming and don't know much about it. Can you please tell me what does 'CUDA compute capability' mean? When I use the following code on my university server, it showed me the following result. for (device = 0; device < deviceCount; ++device) { cudaDeviceProp deviceProp; cudaGetDeviceProperties(&deviceProp, device); printf("\nDevice %d has compute capability %d.%d.\n", device, deviceProp.major, deviceProp.minor); } RESULT: Device 0 has compute capability 4199672.0. Device 1 has compute capability 4199672.0. Device 2 has compute capability 4199672.0. . .