datetime-format

I'm looking for a way to convert dates given in the format YYYYmmdd to an np.array with dtype='datetime64'. The dates are stored in another np.array but with dtype='float64'. I am looking for a way to achieve this by avoiding Pandas! I already tried something similar as suggested in this answer but the author states that "[...] if (the date format) was in ISO 8601 you could parse it directly using numpy, [...]". As the date format in my case is YYYYmmdd which IS(?) ISO 8601 it should be somehow possible to parse it directly using numpy. But I don't know how as I am a total beginner in python

I am writing files to my harddrive,The filename is build like this: String.Format("{0:yyyy-MM-dd_hh-mm-ss}.txt", DateTime.Now) So the filename is "2010-09-20_09-47-04.txt" for example. Now I want to show those filenames in a dropdown, but with another format. The format should be dd.MM.yyyy HH:mm:ss. How can I do that, or is there a better approach? Thanks :) Besnik I tried this on console and it did the job. Imports System.Globalization Module Module1 Sub Main() Dim enUS As New CultureInfo("en-US") Dim d As String = Format(DateTime.Now, "yyyy-MM-dd_hh-mm-ss") Dim da As Date = DateTime

If I have a bunch of data with date & time in UTC format , how can I convert them to EST . It can determine when they will be -4(in summer) and - 5(in winter) automatically every year? Thanks You'll need to use the pytz module (available from PyPI): import pytz from datetime import datetime est = pytz.timezone('US/Eastern') utc = pytz.utc fmt = '%Y-%m-%d %H:%M:%S %Z%z' winter = datetime(2016, 1, 24, 18, 0, 0, tzinfo=utc) summer = datetime(2016, 7, 24, 18, 0, 0, tzinfo=utc) print winter.strftime(fmt) print summer.strftime(fmt) print winter.astimezone(est).strftime(fmt) print summer.astimezone

I have $date = $run['at']; which gives me 2013-06-03T16:52:24Z (from a JSON input). To transform it to get for example " d M Y, H:i " I use $date = new DateTime($run['at']); echo $date->format('d M Y, H:i'); Problem is I need the date in italian. And the only function that supports set_locale is strftime . How can I "wrap" DateTime::format with strftime (or replace, dunno)? setlocale(LC_TIME, 'it_IT.UTF-8'); $date = new DateTime($run['at']); strftime("%d %B", $date->getTimestamp()) ... worked. :) I believe the "proper" way should be using DateTimeZone 来源： https://stackoverflow.com/questions

I have a date string "2012-11-14T06:57:36+0000" that I want to convert to the following format "Nov 14 2012 12:27" . I have tried a lot of solutions including Convert UTC Date to datetime string Javascript . But nothing could help me. The following code worked for me in android. But for ios it displays as invalid date var date = "2012-11-14T06:57:36+0000"; //Calling the function date = FormatDate(date); //Function to format the date function FormatDate(date) { var newDate = new Date(date); newDate = newDate.toString("MMMM"); return (newDate.substring(4,21)); } Can anyone help me? Thanks in