cycle

Why Akka streams cycle doesn't end in this graph?

有些话、适合烂在心里 提交于 2019-11-28 14:17:32
I would like to create a graph that loop n times before going to sink. I've just created this sample that fulfill my requirements but doesn't end after going to sink and I really don't understand why. Can someone enlighten me? Thanks. import akka.actor.ActorSystem import akka.stream.scaladsl._ import akka.stream.{ActorMaterializer, UniformFanOutShape} import scala.concurrent.Future object test { def main(args: Array[String]) { val ignore: Sink[Any, Future[Unit]] = Sink.ignore val closed: RunnableGraph[Future[Unit]] = FlowGraph.closed(ignore) { implicit b => sink => { import FlowGraph.Implicits

itertools.cycle().next()?

百般思念 提交于 2019-11-28 08:02:00
Well, I was using itertools.cycle().next() method with Python 2.6.6, but now that I updated to 3.2 I noticed that itertools.cycle() object has no method next() . I used it to cycle a string in the spin() method of a Spinner class. So if we cycle the tuple ('|', '/', '-', '\\', '|', '/', '-') , it'll print: | , / , - , \ , | , / , - , | , / and so on... I've searched the release notes of Python 3.0, 3.1 and 3.2 and didn't noticed any change on this. When this have changed? Is there any simple alternative to achieve the same functionality as before? Thank you in advance. d0ugal iter.next() was

Scala Graph Cycle Detection Algo 'return' needed?

一笑奈何 提交于 2019-11-28 02:00:07
问题 I have implemented a small cycle detection algorithm for a DAG in Scala. The 'return' bothers me - I'd like to have a version without the return...possible? def isCyclic() : Boolean = { lock.readLock().lock() try { nodes.foreach(node => node.marker = 1) nodes.foreach(node => {if (1 == node.marker && visit(node)) return true}) } finally { lock.readLock().unlock() } false } private def visit(node: MyNode): Boolean = { node.marker = 3 val nodeId = node.id val children = vertexMap.getChildren

Why increase pointer by two while finding loop in linked list, why not 3,4,5?

白昼怎懂夜的黑 提交于 2019-11-27 16:51:43
I had a look at question already which talk about algorithm to find loop in a linked list. I have read Floyd's cycle-finding algorithm solution, mentioned at lot of places that we have to take two pointers. One pointer( slower/tortoise ) is increased by one and other pointer( faster/hare ) is increased by 2. When they are equal we find the loop and if faster pointer reaches null there is no loop in the linked list. Now my question is why we increase faster pointer by 2. Why not something else? Increasing by 2 is necessary or we can increase it by X to get the result. Is it necessary that we

Disappearing images in IE8 jQuery Cycle

[亡魂溺海] 提交于 2019-11-27 16:07:20
http://www.lunatestsite.co.uk/products/lifestation Cannot for the life of me fix this. Only in IE8 so far. I had the same issue on the homepage cycle, but managed to fix by declaring width, height and background: none !important on the img's in question. I thought it might be a png issue, but the same happens with jpgs: http://www.lunatestsite.co.uk/test-disappearing-jpgs Same result: often a flicker of the first of the two images in the slideshow, then disappears. Any ideas at all appreciated. SOLVED: My original fix worked for this in the end too : adding the background: none important!, and

Cycle detection in linked list with the Hare and Tortoise approach

北慕城南 提交于 2019-11-27 13:55:10
问题 I understand that in order to detect a cycle in a linked list I can use the Hare and Tortoise approach, which holds 2 pointers (slow and fast ones). However, after reading in wiki and other resources, I do not understand why is it guaranteed that the two pointers will meet in O(n) time complexity. 回答1: Here's an attempt at an informal proof. The shape of the cycle doesn't matter. It can have a long tail, and a loop towards the end, or just a loop from the beginning to the end without a tail.

help in the Donalds B. Johnson's algorithm, i cannot understand the pseudo code (PART II)

雨燕双飞 提交于 2019-11-27 02:15:38
i cannot understand a certain part of the paper published by Donald Johnson about finding cycles (Circuits) in a graph. More specific i cannot understand what is the matrix Ak which is mentioned in the following line of the pseudo code : Ak:=adjacency structure of strong component K with least vertex in subgraph of G induced by {s,s+1,....n}; to make things worse some lines after is mentins " for i in Vk do " without declaring what the Vk is... As far i have understand we have the following: 1) in general, a strong component is a sub-graph of a graph, in which for every node of this sub-graph

itertools.cycle().next()?

家住魔仙堡 提交于 2019-11-27 02:02:27
问题 Well, I was using itertools.cycle().next() method with Python 2.6.6, but now that I updated to 3.2 I noticed that itertools.cycle() object has no method next() . I used it to cycle a string in the spin() method of a Spinner class. So if we cycle the tuple ('|', '/', '-', '\\', '|', '/', '-') , it'll print: | , / , - , \ , | , / , - , | , / and so on... I've searched the release notes of Python 3.0, 3.1 and 3.2 and didn't noticed any change on this. When this have changed? Is there any simple

How to break outer cycle in Ruby?

一世执手 提交于 2019-11-26 19:50:33
In Perl, there is an ability to break an outer cycle like this: AAA: for my $stuff (@otherstuff) { for my $foo (@bar) { last AAA if (somethingbad()); } } (syntax may be wrong), which uses a loop label to break the outer loop from inside the inner loop. Is there anything similar in Ruby? Jörg W Mittag What you want is non-local control-flow, which Ruby has several options for doing: Continuations, Exceptions, and throw / catch Continuations Pros: Continuations are the standard mechanism for non-local control-flow. In fact, you can build any non-local control-flow (subroutines, procedures,

Why increase pointer by two while finding loop in linked list, why not 3,4,5?

白昼怎懂夜的黑 提交于 2019-11-26 18:46:14
问题 I had a look at question already which talk about algorithm to find loop in a linked list. I have read Floyd's cycle-finding algorithm solution, mentioned at lot of places that we have to take two pointers. One pointer( slower/tortoise ) is increased by one and other pointer( faster/hare ) is increased by 2. When they are equal we find the loop and if faster pointer reaches null there is no loop in the linked list. Now my question is why we increase faster pointer by 2. Why not something else