criteria

Restrictions

三世轮回 提交于 2019-11-30 01:05:09
Criteria cri = session.createCriteria(Student.class); cri.add(Example.create(s)); //s是一个Student对象 list cri.list(); 实质:创建一个模版,比如我有一个表serial有一个 giftortoy字段,我设置serial.setgifttoy("2"), 则这个表中的所有的giftortoy为2的数据都会出来 2: QBC (Query By Criteria) 主要有Criteria,Criterion,Oder,Restrictions类组成 session = this.getSession(); Criteria cri = session.createCriteria(JdItemSerialnumber.class); Criterion cron = Restrictions.like("customer",name); cri.add(cron); list = cri.list(); ============================== 比较运算符 HQL运算符 QBC运算符 含义 = Restrictions.eq() 等于 <> Restrictions.not(Exprission.eq()) 不等于 > Restrictions.gt() 大于

Restrictions

大憨熊 提交于 2019-11-30 01:05:03
Criteria cri = session.createCriteria(Student.class); cri.add(Example.create(s)); //s是一个Student对象 list cri.list(); 实质:创建一个模版,比如我有一个表serial有一个 giftortoy字段,我设置serial.setgifttoy("2"), 则这个表中的所有的giftortoy为2的数据都会出来 2: QBC (Query By Criteria) 主要有Criteria,Criterion,Oder,Restrictions类组成 session = this.getSession(); Criteria cri = session.createCriteria(JdItemSerialnumber.class); Criterion cron = Restrictions.like("customer",name); cri.add(cron); list = cri.list(); ============================== 比较运算符 HQL运算符 QBC运算符 含义 = Restrictions.eq() 等于 <> Restrictions.not(Exprission.eq()) 不等于 > Restrictions.gt() 大于

Subquery in select clause with JPA Criteria API

北战南征 提交于 2019-11-29 23:13:14
I'm trying, as in title, to insert a subquery in select clause like in this simple SQL: SELECT id, name, (select count(*) from item) from item this is obviously only a mock query just to make my point. (The point would be to get the last invoice for each item returned by the query.) I've tried this: CriteriaBuilder cb = em.getCriteriaBuilder(); CriteriaQuery<Tuple> c = cb.createTupleQuery(); Root<Item> item= c.from(Item.class); Subquery<Long> scount = c.subquery(Long.class); Root<Item> sarticolo = scount.from(Item.class); scount.select(cb.count(sitem)); c.multiselect(item.get("id"),item.get(

truncate/delete from given the entity class

偶尔善良 提交于 2019-11-29 17:54:48
问题 I have my entity class available via a method. I'm trying to figure out, how via the JPA JPQL or Criteria API's I could issue a truncate or delete from. I think that the criteria api is more natural for working with classes, and truncate is a faster operation so these are prefered. This is what I put together so far, but not sure what to add/change about it. CriteriaBuilder cb = this._em().getCriteriaBuilder(); cb.createQuery( _entityClass() ).from( _entityClass() ); note: _entityClass

Refresh MS Access Form/Query Based On Combobox Value

吃可爱长大的小学妹 提交于 2019-11-29 16:58:19
Pretty simple explanation. I have a table with 10 entries, 5 entries with the year 2010 and 5 entries with 2011 in a column. In the query I have, I use Like *2010 to filter out all entries equal 2010 and display onl those records. On my form, I have combobox being populated with each unique year (from a different table). So my combobox values are 2010 and 2011. Is it possible, when I select say 2011, I trim the right 4 characters and use as my Like criteria to refresh and requery the form, all done within VBA? You can refer to the value of a control in a query run from within an Access session

SetFetchMode call ignored

人盡茶涼 提交于 2019-11-29 15:28:15
I have a problem with SetFetchMode call in Criteria API in following query: DetachedCriteria.For<User>() .Add<User>(u => u.Status == UserStatus.Live) .CreateAlias("UniqueId", "uid") .CreateAlias("Companies", "comp") .Add(Restrictions.Disjunction() .Add(Restrictions.Like("uid.Uid", context.Text, MatchMode.Anywhere)) .Add(Restrictions.Like("comp.Name", context.Text, MatchMode.Anywhere))) .SetFetchMode("Companies", FetchMode.Eager)); My Classes: public class User : EntityBase<int> { public virtual UniqueId UniqueId { get; set; } public virtual ISet<Company> Companies { get; set; } } public class

Hibernate Criteria API - Filtering collection property

你。 提交于 2019-11-29 15:21:19
问题 I have such entity: @Entity public class Album { private Integer id; private Integer ownerId; private String name; private String description; private Date created; @OneToMany @JoinColumn(name = "albumId") private Set<AlbumUser> users = new HashSet<AlbumUser>(); @OneToMany @JoinColumn(name = "albumId") private Set<Picture> pictures = new HashSet<Picture>(); } and another one: @Entity public class Picture { private Integer id; private Integer creatorId; private Integer albumId; private Date

Hibernate Criteria 用法

感情迁移 提交于 2019-11-29 12:50:16
Hibernate 设计了 CriteriaSpecification 作为 Criteria 的父接口,下面提供了 Criteria和DetachedCriteria 。 Criteria 和 DetachedCriteria 的主要区别在于创建的形式不一样, Criteria 是在线的, 它是由 Hibernate Session 进行创建的,session关闭Criteria跟随消亡 ;而 DetachedCriteria 是离线的,创建时无 需 Session,允许重复使用。DetachedCriteria 提供了 2 个静态方法 forClass(Class) 或 forEntityName(Name) 进行DetachedCriteria 实例的创建。 Spring 的框架提供了getHibernateTemplate ().findByCriteria(detachedCriteria) 方法可以很方便地根据DetachedCriteria 来返回查询结 果。 Criteria 和 DetachedCriteria 均可使用 Criterion 和 Projection 设置查询条件。可以设 置 FetchMode( 联合查询抓取的模式 ) ,设置排序方式。对于 Criteria 还可以设置 FlushModel (冲刷 Session 的方式)和 LockMode

关于Hibernate的Criteria查询

一个人想着一个人 提交于 2019-11-29 12:49:04
如同大家所了解的Hibernate框架技术是现今的主流SSH之一的技术,Cirteria查 询 诞生让的我们看到一种全新的方式(不得不说独特),不用自己编写的SQL或HQL(Hibernate Query Languae)语句 (这对于不会编写或没有学好这门技术的码农来说是一大福音啊),由Hibernate产生SQL查询语句。Criteria查询采用面向对象的方式封装查询条件,对SQL语句进行封装,采用对象的方式来组合查询,在由Hibernate产生SQL语句。 本人也是最近才学,仅供一些初学者参考。感觉要学好一门框架不是一件容易的事。 Cirteria 查询先要创建 Query 对象这点跟HQL 查询类似 但传入的参数不同 ,Cirteria传入的 是对应的实体类的类型对象 如: HQL查询: String hql="from Student(实体类名)";//注意这里的实体类名 对大小写敏感 Query query = session.createQuery(hql); Cirteria 查询: Criteria criteria = session.createCriteria(Users.class); // 对大小写敏感 Cirteria 本身是个容器 ,若想设定查询条件,则要使用Criteria的add()方法加入“条件实例”

Is it possible to get the SQL alias of a join table for a Hibernate sqlRestriction?

你离开我真会死。 提交于 2019-11-29 12:19:53
问题 I have a Person class which has a String collection of aliases representing additional names that person may go by. For example, Clark Kent may have aliases "Superman" and "Man of Steel". Dwight Howard also has an alias of "Superman". @Entity class Person { @CollectionOfElements(fetch=FetchType.EAGER) Set<String> aliases = new TreeSet<String>(); Hibernate creates two tables in my database, Person and Person_aliases. Person_aliases is a join table with the columns Person_id and element. Let's