Subquery in select clause with JPA Criteria API

北战南征 提交于 2019-11-29 23:13:14

It is supported in JPA 2.1 and Hibernate 5.0. You just had to add getSelection() to the subquery argument in the multiselect of the main query.

c.multiselect(item.get("id"),item.get("nome"), scount.getSelection());

Take a look at this working example:

CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<NotificationInfo> cq = builder.createQuery(NotificationInfo.class); //wrapper class
Root<Notification> n = cq.from(Notification.class); //root entity

//Subquery
Subquery<Long> sqSent = cq.subquery(Long.class);
Root<NotificationUser> sqSentNU = sqSent.from(NotificationUser.class);
sqSent.select(builder.count(sqSentNU));
sqSent.where(
        builder.equal(sqSentNU.get(NotificationUser_.notification), n),  //join subquery with main query
        builder.isNotNull(sqSentNU.get(NotificationUser_.sendDate))
);

cq.select(
    builder.construct(
            NotificationInfo.class,
            n.get(Notification_.idNotification),
            n.get(Notification_.creationDate),
            n.get(Notification_.suspendedDate),
            n.get(Notification_.type),
            n.get(Notification_.title),
            n.get(Notification_.description),
            sqSent.getSelection()
    )
);
em.createQuery(cq).getResultList();

JPA does not support sub-queries in the select clause.

You need to either change your query so as not to use require the sub-query in the select clause, execute multiple queries, or use a native SQL query.

You need to coalesce your subquery result:

Expression<ResultType> expression = criterioaBuilder.coalesce(subquery, criteriaBuilder.literal((ResultType) defaultResult);
query.select(expression);

JPA now supports sub-queries in the select clause.

EDIT:
JPA 2.1 JPQL BNF supports sub-queries in select clause even if it's not required. As far as I know Eclipselink Supports this and Hibernate too (tested in 5.1).

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