compilation

问题 I noticed that calculating the integer part of square root of uint64_t is much more complicated than of int64_t . Please, does anybody have an explanation for this? Why is it seemingly much more difficult to deal with one extra bit? The following: int64_t sqrt_int(int64_t a) { return sqrt(a); } compiles with clang 5.0 and -mfpmath=sse -msse3 -Wall -O3 to sqrt_int(long): # @sqrt_int(long) cvtsi2sd xmm0, rdi sqrtsd xmm0, xmm0 cvttsd2si rax, xmm0 ret But the following: uint64_t sqrt_int(uint64_t

问题 A couple of years ago I asked a question how to reduce size of executables. Using MinGW compiler, stripping symbols ( -s option) helped to reduce 50%+ of the size. Why the stripping is not default - is there any good reason why NOT to strip the symbols in some scenarios then? I'd like to understand it more deeply: today, I just vaguely know that symbols are involved in linking library. Are they needed in executable and do they affect executing speed? 回答1: MinGW is an acronym for "Minimalist

问题 A couple of years ago I asked a question how to reduce size of executables. Using MinGW compiler, stripping symbols ( -s option) helped to reduce 50%+ of the size. Why the stripping is not default - is there any good reason why NOT to strip the symbols in some scenarios then? I'd like to understand it more deeply: today, I just vaguely know that symbols are involved in linking library. Are they needed in executable and do they affect executing speed? 回答1: MinGW is an acronym for "Minimalist

问题 It is frequently mentioned that the -std flag should be used to specify the standard that one wishes to use when compiling a C++ program (e.g., -std=c++11 or -std=gnu++11 ). A related question that is not typically addressed (at least as far as I can tell; see, for instance, the highly-upvoted comment by Dennis under the selected answer by Oskar N.) is how to determine what the default C++ standard that is being used by the compiler is . I believe that it is possible to tell by looking at the

问题 I'm currently taking a microservice online course where I deploy small go apps to docker containers. The long and ugly command line to build the binaries is this one: go build --tags netgo --ldflags '-extldflags "-lm -lstdc++ -static"' till now I just used go install to compile my go app. Can anyone explain this command to me? 回答1: --tags netgo is used to use go lang network stack --ldflags sets the flags that are passed to 'go tool link' The value of the args to ldflags is explained in the

问题 I have compiled my python code (in Windows) with the following cython and gcc commands:- cython --embed -o hello.c hello.py gcc -municode -mthreads -Wall -O -IC:\Python37\include -LC:\Python37\libs hello.c -lpython37 -Wl,--subsystem,windows -o hello.exe (I am using modules such as request, pysimpleguiqt and fdb in hello.py) The resulting exe requires python installation to execute. Is there any way to compile it without the need of python installation at runtime? 回答1: Is there any way to

问题 I want to load a class form a .cs file and use it in another code. Assume I have a .cs file which contains code like that: //some imports public class Commands { //a lot of commands } What I am trying is to load this class from a file using CSharpCodeProvider or whatever and create a list of Commands. A piece of code from a console app. list<Commands> lst; The question is how can I load Commands class dynamically (at runtime) (without restarting the console app or starting VS) and create the

问题 I'm experimenting with Cython and possibilities of code obfuscation (article). In that article especially noted: When the compilation is done there’s no way to reverse compiled libraries back to readable Python source code! I use this question info to compile my code in standalone executable. In my understanding and as mentioned in article 1, Cython translates Python code into C code, with correspond calls of Python library (is this correct?). In other wolds, we have only C file as output,

问题 I'm experimenting with Cython and possibilities of code obfuscation (article). In that article especially noted: When the compilation is done there’s no way to reverse compiled libraries back to readable Python source code! I use this question info to compile my code in standalone executable. In my understanding and as mentioned in article 1, Cython translates Python code into C code, with correspond calls of Python library (is this correct?). In other wolds, we have only C file as output,

问题 I am trying to compile Protoc library but It just keeps giving me the error of No Such Directory even though it is there I am following Google's Photobuf compilation steps I have added Protoc to PATH environment variable as well. But it simply won't see the object_detection/protos directory protoc object_detection/protos/*.proto --python_out=. The directory and the files are clearly there 回答1: Same issue with you. I have been installed protoc with anaconda3,but it is useless. This is my