compilation

I'm working on a Ruby script that will need to be deployed onto systems without a ruby interpreter. It will need to run on FreeBSD systems which uses the ELF format. I know there is a ruby2exe project to compile ruby scripts to run on Windows, but is it easy or even possible to do that on other operating systems? Have you checked whether Rubinius or JRuby would allow you to precompile your code? Aside from bytecode that requires a VM to run, Ruby cannot be compiled. It is an interpreted langauge and as such requires an interpreter. ruby2exe packages a ruby interpreter and runtime library with

I recently updated R to 3.1.0. I tried to move my packages over to 3.1 inside the R.Framework (I'm running OSX Mavericks) and somehow made a mess of it, so did a complete uninstall of everything before a clean install. When reinstalling packages I had no issues until I hit the forecast package which yields the following error: package ‘forecast’ is available as a source package but not as a binary Warning in install.packages : package ‘forecast’ is not available (for R version 3.1.0) I actually had R 3.1.0 and both forecast and hts working together prior to the reinstall so I suspect the

Background I have an sbt-managed Scala project that uses the usual sbt project layout for Scala projects with macros, i.e., a subproject that contains the macros a main project that is the actual application and that depends on the macro subproject. The macros are macro annotations which, in essence, generate companion objects for regular classes. The generated companion objects declare, amongst other members, apply/unapply methods. I used the sbt-idea plugin to generate a corresponding IntelliJ IDEA project, and I use the sbt console from IDEA's sbt-plugin to compile and run my Scala

fileA.cpp： #include <iostream> extern int iA; extern int iB= iA; int main() { std::cout<<iA<<','<<iB; } fileB.cpp extern int iB; extern int iA = 2*iB; Compiled and linked and ran, out come in the debug and release mode is 0,0 My question is how it works, why there is no issue in linking stage? I'm using VC++2003. The initialiser overrides the extern keyword, so there's nothing "magical" about this: you're just declaring and defining two completely unrelated variables in different functions. [C++14: 3.1/2]: A declaration is a definition unless it declares a function without specifying the

I am trying to compile a library file using other library files. I am using the following line in my makefile to create gameobject.o: lib/gameobject.o: src/gameobject.cpp src/vector.hpp lib/objectevent.o lib/sprite.o g++ $^ -c -o $@ $(SFML_FLAGS) All the dependencies comile correctly, but I get the following error when it tries to compile gameobject.o: g++: fatal error: cannot specify -o with -c, -S or -E with multiple files I'm still a bit new to using make/separating compilation, so I'm not quite sure what I should do. Do I just have to compile it without setting an output? Do I have to

Often when I'm working on a project with others, the amount of library paths and include paths that get sourced by the compiler in the Makefile get more numerous as time goes by. Also the paths can get very long as well. Here's an example: g++ -c -pipe -O2 -Wall -W -DQT_BOOTSTRAPPED -DQT_MOC -DQT_NO_CODECS -DQT_LITE_UNICODE -DQT_NO_LIBRARY -DQT_NO_STL -DQT_NO_COMPRESS -DQT_NO_DATASTREAM -DQT_NO_TEXTSTREAM -DQT_NO_TEXTCODEC -DQT_NO_UNICODETABLES -DQT_NO_THREAD -DQT_NO_REGEXP -DQT_NO_QOBJECT -DQT_NO_SYSTEMLOCALE -DQT_NO_GEOM_VARIANT -DQT_NO_USING_NAMESPACE -D_LARGEFILE64_SOURCE -D_LARGEFILE

I use the following in my C++ code: int a = 0, b = a; I would like to know if this behaviour is reliable and well defined (left to right order of name declaration) and that my code will not break with other compilers with an undeclared name error. If not reliable, I would break the statement: int a = 0; int b = a; Thank you. I believe the answer is no. It is subject to core active issue 1342 which says: It is not clear what, if anything, in the existing specification requires that the initialization of multiple init-declarators within a single declaration be performed in declaration order. We

When I define Wrapper as value class(extending AnyVal): class Wrapper(val string: String) extends AnyVal def wrapperHolder(w: Wrapper): {def wrapper: Wrapper} = new { def wrapper: Wrapper = w } I have following compile error for wrapperHolder: Error:(5, 22) Result type in structural refinement may not refer to a user-defined value class def wrapper: Wrapper = w Why it doesn't work for value class? 来源： https://stackoverflow.com/questions/52678323/result-type-in-structural-refinement-may-not-refer-to-a-user-defined-value-class