combinations

问题 Lets say I have an array called arr = [1,2,3,4] How can I generate all the possible combinations with minimum 2 arguments that end up looking like [1,2] [1,3] [1,4] [1,2,3] [1,2,4] [1,2,3, 4] [2,3] [2,4] and so on and so forth? Nothing Im trying works. I cant seem to use itertools.combinations or permutations because I need to know the argument size and I cant seem to use itertools.products because that will take minimum one argument from each of a list of lists that looks like this [[1],[2],

问题 I am looking to use R's expand.grid to comprehensively enumerate and investigate options for hierarchical clustering analysis. I have a final function acc which will take a matrix and analyse it for performance measures like accuracy, precision, F1 etc., returning a named list (with accuracy, F1, etc.): the ultimate output I'm looking for is a table where all the hyperparameter combinations are listed and, in columns next to them, the different performance measures (accuracy, F1,...). The

问题 Since the groups of 6 represent dice, the order of the integers in these groups does not matter. The order of the groups within each set does matter, but to check each one it would be simple to find the permutations of each set, which I can do. Now, I've come up with a way to achieve all this, the problem is efficiency. I want to check each set but so far I've only come up with a way using: for i in itertools.combinations(num, 6): W.append([i]) print(W) print("Done building list of ",len(W),"

问题 I have a matrix which is 9x10000 size. So rows are R1, R2, upto R9. I want to generate all possible combination of the rows such as [R1;R2] [R1;R3].. [R1;R9] [R1;R2;R3]...[R1;R2;R4]... [R1;R2:R3;R4;..R8] I am currently doing this using for loops. Is there any better way of doing this. 回答1: Basically, counting up the binary from 1 to 2^9-i indicates which rows need to be selected: M=... your matrix S=dec2bin(1:2^size(M,1)-1)=='1'; allSubsets=cell(size(S,1),1); for ix=1:size(S,1) allSubsets{ix}

问题 Problem statement I want to get all possible combinations out of my list (including the empty list). My code so far is: def combination(l): result = [] for item in range(len(l)): cut_list = l[:item] + l[item + 1:] if len(cut_list) > 1: combination(cut_list) elif len(cut_list) == 1: result += cut_list return result print(combination([1, 2, 3])) My output is an empty List [] i want this Output: [[], [1], [2], [3], [1, 2], [1, 3], [2, 3], [1, 2, 3]] I am pretty sure something with my return is

问题 My goal is to create a part of code that would generate all possible combinations without duplicates (combinations with same elements, no matter what their sequence is) with data from a JSON file. My JSON file looks like this: [ { "COLLECTION": "Assault", "WEAPON": "SG 553", "SKIN": "Tornado", "GRADE": "Consumer Grade" }, { "COLLECTION": "Assault", "WEAPON": "UMP-45", "SKIN": "Caramel", "GRADE": "Consumer Grade" }, { "COLLECTION": "Vertigo", "WEAPON": "Five-SeveN", "SKIN": "Candy Apple ",

问题 I have three variables: X, Y, and Z. I want to find all the combinations of X, Y and Z that add up to 100. X, Y and Z can only take values between [0,100]. The ouput should look somehtinkg like this: X Y Z Sum 100 0 0 100 99 1 0 100 99 0 1 100 98 2 0 100 98 1 1 100 98 0 2 100 and so on... Any suggestion on how to get all the possible combinations? 回答1: Since you're limited to 1:100 on only three columns, this is easy to brute force. Would need a more clever solution if the range was larger.

问题 I have an existing scheme for products variations. I want to create a combination of each production time, quantities and variation options. I will create a selection form by accessing the quantities, production times, variation and variation options from the product. table_groups +------------+ | id | title | +----+-------+ | 1 | rug | +----+-------+ table_days +----+----------+------+ | id | group_id | day | +----+----------+------+ | 1 | 1 | 1 | | 2 | 1 | 2 | | 3 | 1 | 3 | +----+----------

问题 I am looking to find and print all possible combinations of the set (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12) of length 5. There should be 13 choose 5 combinations (6188) because order does NOT matter, and repetition is allowed. I found this code and was using it: from itertools import product for item in product([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], repeat=5): print(item) However, this is not printing all 6188 combinations. Trying to figure out how to tweak the code so it spits out

问题 I am looking to find and print all possible combinations of the set (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12) of length 5. There should be 13 choose 5 combinations (6188) because order does NOT matter, and repetition is allowed. I found this code and was using it: from itertools import product for item in product([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], repeat=5): print(item) However, this is not printing all 6188 combinations. Trying to figure out how to tweak the code so it spits out