code-translation

问题 I would like to convert this code which is written in MATLAB to C: matrix = [1 2 3; 4 5 6; 7 8 10] dis=zeros(9); for i=1:3 for j=1:3 dis(i,j)=sqrt(sum (abs((matrix(i,:)-matrix(j,:))))^2); end end The output is as follows: 0 9 19 9 0 10 19 10 0 Here is what I came up with in C: #include <stdio.h> #include <math.h> int main() { double distance[3][3] = {0}; double myArray[3][3] = { {1, 2, 3}, {4 , 5, 6}, {7, 8, 9} }; int i, j; for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { distance[i][j] =

来源： https://stackoverflow.com/questions/8788866/tool-to-convert-translate-c-to-go

问题 I'm trying to retrieve a X509Certificate from an eToken Pro 72K and verify It's authenticity. I have been able to see the certificate is present the X509Keystore.Certificates with the eToken inserted using the Keystore as new X509Keystore(StoreName.My, StoreLocation.CurrentUser) . I have a hard-coded certificate that I turn into a X509Certificate2 as: //C# code //HardCoded private const string CERTIFICATE = "-----BEGIN CERTIFICATE-----

问题 I'm trying to retrieve a X509Certificate from an eToken Pro 72K and verify It's authenticity. I have been able to see the certificate is present the X509Keystore.Certificates with the eToken inserted using the Keystore as new X509Keystore(StoreName.My, StoreLocation.CurrentUser) . I have a hard-coded certificate that I turn into a X509Certificate2 as: //C# code //HardCoded private const string CERTIFICATE = "-----BEGIN CERTIFICATE-----

问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I am not looking for a necessarily super-robust solution with a 10-year track record, but for something that can be used in a real applications, and goes beyond just being able to run an Hello World example. My preference is to run the compiler on the server, so I can compile Haskell

问题 I need to change C code from below to a MIPS code but I am new to MIPS and stuck with it. Here is the C code: int main() { int a, b, result; if(a == b) result = a*b; else result = assess(a, b); return result; } int assess(int a, int b) { if(b<a) return upgrade(a, b); else return demote(a, b); } int upgrade(int a, int b) { return 4*(a+b); } int demote(int a, int b) { return 4*(b-a); } Here is MIPS code that I wrote, which isn't working (I am aware there are major errors and wrongs). Because I

问题 I use Hedge to transfer Magic Lantern video files shot on my Canon 5D Mark III. On OS X, I'm able to use Automator to set up a bash script, to execute an mlv_dump to transfer the files from MLV into cDNG sequences. The script I use currently is: cd "$(dirname "$1")" for f in "$@"; do if [[ -f $f ]]; then filename=${f##*/}; folder=${filename%.*} mkdir "${folder}"; ~/mlv_dump --dng $f -o ${folder}/${folder}_; fi done Can this easily translate into a Windows equivalent? Thanks, Thomas 回答1: As

问题 This is the code I want translated into Racket: public static ArrayList<Integer> convert(int k, int n) { ArrayList<Integer> lst = new ArrayList<>(); while (k / n != 0) { lst.add(k % n); k = k/n; } lst.add(k % n); return lst; } e.g. in Racket the (convert 23 2) should return the binary of the decimal 23 , which is (list 1 0 1 1 1) . This is what I got so far: (define (convert k n) (cond [(> (/ k n) 0) (list(modulo k n))] [else 0] )) It works for the first element of the list. Thanks for any

问题 I translated the MATLAB cart2sph and sph2cart functions to python in this way. import numpy as np def cart2sph(x,y,z): azimuth = np.arctan2(y,x) elevation = np.arctan2(z,np.sqrt(x**2 + y**2)) r = np.sqrt(x**2 + y**2 + z**2) return azimuth, elevation, r def sph2cart(azimuth,elevation,r): x = r * np.cos(elevation) * np.cos(azimuth) y = r * np.cos(elevation) * np.sin(azimuth) z = r * np.sin(elevation) return x, y, z I didn't find any library in numpy that translate the MATLAB change of

问题 Is there a software converter out there that can automatically convert this python code to PHP? #!/usr/bin/python import math def calcNumEntropyBits(s): if len(s) <= 0: return 0.0 symCount = {} for c in s: if c not in symCount: symCount[c] = 1 else: symCount[c] += 1 entropy = 0.0 for c,n in symCount.iteritems(): prob = n / float(len(s)) entropy += prob * (math.log(prob)/math.log(2)) if entropy >= 0.0: return 0.0 else: return -(entropy*len(s)) def testEntropy(s): print "Bits of entropy in '%s'