clone

Cloning objects without Serialization

早过忘川 提交于 2019-11-27 09:43:22
I've found numerous solutions here at SO and elsewere that deal with deep clone of object via serialization/deserialization (into memory and back). It requires that classes to be cloned are marked with [Serializable] . I happen to have my classes (well most of them) marked with [DataContract] because I use DataContractSerializer to serialize into XML. I only introduced [Serializable] attribute because of the need for deep clone of some of these class instances. However, now something happened to serialization/deserialization via the DCS because it does not work anymore - errors about expecting

How to remove the selected element during a clone() operation

有些话、适合烂在心里 提交于 2019-11-27 08:20:40
问题 I have a select box that gets cloned. I want to remove the user's previous selection from each cloned select box. Here is the method that does the clone() : function addselect(s){ $('#product_categories > .category_block:last').after( $('#product_categories > .category_block:last').clone() ); set_add_delete_links(); return false; } function set_add_delete_links(){ $('.remove_cat').show(); $('.add_cat').hide(); $('.add_cat:last').show(); $("#product_categories > .category_block:only-child >

clone(): ArrayList.clone() I thought does a shallow copy

风格不统一 提交于 2019-11-27 08:03:28
ArrayList<Integer> a=new ArrayList<Integer>(); a.add(5); ArrayList<Integer> b=(ArrayList<Integer>)a.clone(); a.add(6); System.out.println(b.toString()); In the above piece of code, i think clone() does a shallow copy. So, b and a should point to the same memory location. However, when i do b.toString() , the answer is only 5 . Why is 6 also not displayed if clone() does a shallow copy? Bozho Shallow copy does not mean that they point to the same memory location. That would be just an assignment: List b = a; . Cloning creates a new instance, holding the same elements. This means you have 2

Git commands not working in Mac terminal: “dyld: Symbol not found: ___strlcpy_chk” error

你。 提交于 2019-11-27 07:58:48
I am using the command git clone ssh://.... and getting the following error on the terminal: dyld: lazy symbol binding failed: Symbol not found: ___strlcpy_chk Referenced from: /usr/local/git/bin/git Expected in: /usr/lib/libSystem.B.dylib dyld: Symbol not found: ___strlcpy_chk Referenced from: /usr/local/git/bin/git Expected in: /usr/lib/libSystem.B.dylib Trace/BPT trap: 5 KateMak I needed to install command line tools from Xcode. To do so- Open Xcode and hit Cmd + , Click Downloads Install command line tools. http://www.hongkiat.com/blog/mountain-lion-git-fix/ Had the same problem. I have OS

How to prevent NFC tag cloning?

 ̄綄美尐妖づ 提交于 2019-11-27 07:54:05
I am making an app using NFC tags and I have to prevent the NFC tag from cloning. I have seen many other NFC tags which when tried to be cloned, shows a pop up message "Cloning is restricted, tag is secured by secret key", I want the same security for my NFC tag. That depends on what type of tag you use and what level of protection against cloning you want. NFC tags (as defined by the NFC Forum ) have no protection against cloning. Such tags are intended as containers for freely readable data (so called NDEF messages). Anyone could read an NDEF message from one tag and duplicate it to another

git clone fails with “index-pack” failed?

陌路散爱 提交于 2019-11-27 07:23:04
So I created a remote repo that's not bare (because I need redmine to be able to read it), and it's set to be shared with the group (so git init --shared=group). I was able to push to the remote repo and now I'm trying to clone it. If I clone it over the net I get this: remote: Counting objects: 4648, done. remote: Compressing objects: 100% (2837/2837), done. error: git-upload-pack: git-pack-objects died with error.B/s fatal: git-upload-pack: aborting due to possible repository corruption on the remote side. remote: aborting due to possible repository corruption on the remote side. fatal:

Cloning JPA entity

那年仲夏 提交于 2019-11-27 06:57:52
I have a JPA entity already persisted in the database. I would like to have a copy of it (with a different id), with some fields modified. What is the easiest way to do this? Like: setting it's @Id field to null and persisting it will work? will I have to create a clone method for the entity (copying all fields except the @Id )? is there any other approach (like using a cloning framework)? Use EntityManager.detach . It makes the bean no longer linked to the EntityManager. Then set the Id to the new Id (or null if automatic), change the fields that you need and persist. When using EclipseLink,

Clone method for Java arrays

我的梦境 提交于 2019-11-27 06:52:17
What exactly does the clone() method in Java return when used on an array? Does it return a new array with data copied from the original? Ex: int[] a = {1,2,3}; int[] b = a.clone(); When the clone method is invoked upon an array, it returns a reference to a new array which contains (or references) the same elements as the source array. So in your example, int[] a is a separate object instance created on the heap and int[] b is a separate object instance created on the heap. (Remember all arrays are objects). int[] a = {1,2,3}; int[] b = a.clone(); System.out.println(a == b ? "Same Instance":

what is Object Cloning in php?

て烟熏妆下的殇ゞ 提交于 2019-11-27 06:40:59
Can someone explain me what is Object Cloning in php? When should i use clone keyword in php? Decent Dabbler Object cloning is the act of making a copy of an object. As Cody pointed out, cloning in PHP is done by making a shallow copy of the object. This means that internal objects of the cloned object will not be cloned, unless you explicitly instruct the object to clone these internal objects too, by defining the magic method __clone() . If you don't utilize the __clone method, the internal objects of the new object will be references to the same objecs in memory as the internal objects of

Accessing clone() from java.lang.Object

限于喜欢 提交于 2019-11-27 06:18:52
问题 Here is something that I cannot understand. In java.lang.Object the clone() is defined with protected modifier. By definition than it can be accessed by name inside its own class definition, by name inside any class derived from it, and by name in the definition of any class in the same package. Here the Sample class is in another package, and obviously it can't access clone() from the Object class. But as Sample derives implicitly from Object , why is it not able to access it? The definition