cin

Say we have a code: int main() { char a[10]; for(int i = 0; i < 10; i++) { cin>>a[i]; if(a[i] == ' ') cout<<"It is a space!!!"<<endl; } return 0; } How to cin a Space symbol from standard input? If you write space, program ignores! :( Is there any combination of symbols (e.g. '\s' or something like this) that means "Space" that I can use from standard input for my code? It skips all whitespace (spaces, tabs, new lines, etc.) by default. You can either change its behavior, or use a slightly different mechanism. To change its behavior, use the manipulator noskipws , as follows: cin >> noskipws >

I was typing this and it asks the user to input two integers which will then become variables. From there it will carry out simple operations. How do I get the computer to check if what is entered is an integer or not? And if not, ask the user to type an integer in. For example: if someone inputs "a" instead of 2, then it will tell them to reenter a number. Thanks #include <iostream> using namespace std; int main () { int firstvariable; int secondvariable; float float1; float float2; cout << "Please enter two integers and then press Enter:" << endl; cin >> firstvariable; cin >> secondvariable;

From Stroustrup's TC++PL, 3rd Edition, Section 21.3.3: If we try to read into a variable v and the operation fails, the value of v should be unchanged (it is unchanged if v is one of the types handled by istream or ostream member functions). The following example appears to contradict the above quote. Based on the above quote, I was expecting the value of v to remain unchanged -- but it gets zeroed. What's the explanation for this apparent contradictory behaviour? #include <iostream> #include <sstream> int main( ) { std::stringstream ss; ss << "The quick brown fox."; int v = 123; std::cout <<

This question already has an answer here: Need help with getline() 7 answers This is probably a very simple problem but forgive me as I am new. Here is my code: #include <iostream> #include <string> #include <sstream> using namespace std; int main () { string name; int i; string mystr; float price = 0; cout << "Hello World!" << endl; cout << "What is your name? "; cin >> name; cout << "Hello " << name << endl; cout << "How old are you? "; cin >> i; cout << "Wow " << i << endl; cout << "How much is that jacket? "; getline (cin,mystr); stringstream(mystr) >> price; cout << price << endl; system(

I wrote a very basic program in C++ which asked the user to input a number and then a string. To my surprise, when running the program it never stopped to ask for the string. It just skipped over it. After doing some reading on StackOverflow, I found out that I needed to add a line that said: cin.ignore(256, '\n'); before the line that gets the string input. Adding that fixed the problem and made the program work. My question is why does C++ need this cin.ignore() line and how can I predict when I will need to use cin.ignore() ? Here is the program I wrote: #include <iostream> #include <string

I've redirected "cin" to read from a file stream cin.rdbug(inF.rdbug()) When I use the extraction operator it reads until it reaches a white space character. Is it possible to use another delimiter? I went through the api in cplusplus.com, but didn't find anything. It is possible to change the inter-word delimiter for cin or any other std::istream , using std::ios_base::imbue to add a custom ctype facet . If you are reading a file in the style of /etc/passwd, the following program will read each : -delimited word separately. #include <locale> #include <iostream> struct colon_is_space : std: