bufferedinputstream

ESP8266 wifi server to android client

孤街醉人 提交于 2019-12-08 03:06:25
问题 Ive been trying to setup a server using ESP8266 wifi module on a particular port. I'm done with that. I want to receive the message from it now. Whenever I connect using socket.connect(), I am able to detect it in the esp8266. But I cant receive any message, the server sends through the same socket. I am trying to obtain the message using DataInputStream inside a while loop continuously in a async task.Pls let me know if my approach or code is wrong! Thanks! This is my code: package test

InputStream won't close, or takes forever to

梦想的初衷 提交于 2019-12-07 03:10:31
问题 I'm attempting to download an external mp3 into internal storage. However, the files I'm attempting to download are big, so I'm trying to download them in 1MB chunks so that you can begin playing them while the rest is downloaded. Here's my stream code: InputStream is = null; OutputStream os = null; try { HttpClient client = new DefaultHttpClient(); HttpGet get = new HttpGet( url ); HttpResponse response = client.execute( get ); MyLog.d( "Connection established" ); byte[] buffer = new byte

How java.io.Buffer* stream differs from normal streams?

泄露秘密 提交于 2019-12-06 20:46:07
问题 1) How does buffered streams work in background, how do they differ from normal streams and what are the advantage(s) of using them? 2) DataInputStream is also Byte based. But it is having methods to readLine() . What's the point in here? 回答1: From the BufferedInputStream javadoc: A BufferedInputStream adds functionality to another input stream-namely, the ability to buffer the input and to support the mark and reset methods. When the BufferedInputStream is created, an internal buffer array

Java buffered base64 encoder for streams

邮差的信 提交于 2019-12-05 10:38:49
I have lots of PDF files that I need to get its content encoded using base64. I have an Akka app which fetch the files as stream and distributes to many workers to encode these files and returns the string base64 for each file. I got a basic solution for encoding: org.apache.commons.codec.binary.Base64InputStream; ... Base64InputStream b64IStream = null; InputStreamReader reader = null; BufferedReader br = null; StringBuilder sb = new StringBuilder(); try { b64IStream = new Base64InputStream(input, true); reader = new InputStreamReader(b64IStream); br = new BufferedReader(reader); String line;

InputStream won't close, or takes forever to

老子叫甜甜 提交于 2019-12-05 08:17:31
I'm attempting to download an external mp3 into internal storage. However, the files I'm attempting to download are big, so I'm trying to download them in 1MB chunks so that you can begin playing them while the rest is downloaded. Here's my stream code: InputStream is = null; OutputStream os = null; try { HttpClient client = new DefaultHttpClient(); HttpGet get = new HttpGet( url ); HttpResponse response = client.execute( get ); MyLog.d( "Connection established" ); byte[] buffer = new byte[8192]; is = new BufferedInputStream( response.getEntity().getContent(), buffer.length ); os =

How to clone an inputstream in java in minimal time

♀尐吖头ヾ 提交于 2019-12-04 22:50:22
问题 Can someone tell me how to clone an inputstream, taking as little creation time as possible? I need to clone an inputstream multiple times for multiple methods to process the IS. I've tried three ways and things don't work for one reason or another. Method #1: Thanks to the stackoverflow community, I found the following link helpful and have incorporated the code snippet in my program. How to clone an InputStream? However, using this code can take up to one minute (for a 10MB file) to create

How to kill a BufferedInputStream .read() call

心不动则不痛 提交于 2019-12-04 04:20:14
问题 I'm working on writing a program to download very large files (~2GB) from a server. I've written the program to be able to resume partially finished downloads, In order to simulate a bad internet connection, I've been pulling my ethernet cord out of my router while mid-download. Unfortunately, this causes my program to hang on the following call: while((bytesRead = in.read(data)) > 0) (Where bytesRead is an int, in is a BufferedInputStream built from an HttpURLConnection, and data is a byte

How to clone an inputstream in java in minimal time

半世苍凉 提交于 2019-12-03 15:01:46
Can someone tell me how to clone an inputstream, taking as little creation time as possible? I need to clone an inputstream multiple times for multiple methods to process the IS. I've tried three ways and things don't work for one reason or another. Method #1: Thanks to the stackoverflow community, I found the following link helpful and have incorporated the code snippet in my program. How to clone an InputStream? However, using this code can take up to one minute (for a 10MB file) to create the cloned inputstreams and my program needs to be as fast as possible. int read = 0; byte[] bytes =

Should I buffer the InputStream or the InputStreamReader?

梦想与她 提交于 2019-12-03 10:43:16
问题 What are the differences (if any) between the following two buffering approaches? Reader r1 = new BufferedReader(new InputStreamReader(in, "UTF-8"), bufferSize); Reader r2 = new InputStreamReader(new BufferedInputStream(in, bufferSize), "UTF-8"); 回答1: r1 is more efficient. The InputStreamReader itself doesn't have a large buffer. The BufferedReader can be set to have a larger buffer than InputStreamReader . The InputStreamReader in r2 would act as a bottleneck. In a nut: you should read the

How do I peek at the first two bytes in an InputStream?

一笑奈何 提交于 2019-12-03 09:26:06
Should be pretty simple: I have an InputStream where I want to peek at (not read) the first two bytes, i.e. I want the "current position" of the InputStream to stil be at 0 after my peeking. What is the best and safest way to do this? Answer - As I had suspected, the solution was to wrap it in a BufferedInputStream which offers markability. Thanks Rasmus. For a general InputStream, I would wrap it in a BufferedInputStream and do something like this: BufferedInputStream bis = new BufferedInputStream(inputStream); bis.mark(2); int byte1 = bis.read(); int byte2 = bis.read(); bis.reset(); // note: