brackets

How to prevent Sublime Text 2 from swallowing closing brackets, quotes and parentheses?

青春壹個敷衍的年華 提交于 2019-11-28 16:11:44
问题 Sublime has this behaviour which is really annoying sometimes when you have to type in constructions with lots of brackets. When you type ( it adds () and puts the cursor in the middle, all fine, if you however will type ) it will silently swallow the closing bracket. This is really annoying when typing long regexps because the brackets gets unbalanced pretty quick and this is driving me crazy. So you end up with constructions like (([a-z]) . So the question is - is there a way to disable

How to select between brackets (or quotes or …) in Vim?

浪子不回头ぞ 提交于 2019-11-28 14:56:19
I'm sure there used to be a plugin for this kinda stuff, but now that I need it, I can't seem to find it (naturally), so I'll just ask nice and simple. What is the easiest way to select between brackets, or quotes, or generally a list of matching characters? write ( *, '(a)' ) 'Computed solution coefficients:' For example, here I'd like to select (a) , or Computed solution coefficients: . I'm not interested in multiline, just cases which occur on one line. Tim Whitcomb Use whatever navigation key you want to get inside the parentheses, then you can use either yi( or yi) to copy everything

Using Javascript with Brackets in Field Name

两盒软妹~` 提交于 2019-11-28 09:32:45
问题 How do I reference a HTML form element whose name contains brackets? For example, <form name="myForm"> <input type="checkbox" name="myElement[7]" /> </form> I do not have the option of renaming the form element and I cannot use jquery. How would I access this element using javascript alone? I already tried using: alert(document.myForm.myElement\\[7\\].type); The result is "undefined". I also tried the above javascript snipped without the slashes and also got "undefined". What is the correct

Extracting string from within round brackets in Java with regex

坚强是说给别人听的谎言 提交于 2019-11-28 02:22:51
I'm trying to extract a string from round brackets. Let's say, I have John Doe (123456789) and I want to output the string 123456789 only. I have found this link and this regex: /\(([^)]+)\)/g However, I wasn't able to figure out how to get the wanted result. Any help would be appreciated. Thanks! SatyaTNV String str="John Doe (123456789)"; System.out.println(str.substring(str.indexOf("(")+1,str.indexOf(")"))); Here I'm performing string operations. I'm not that much familiar with regex. You need to escape brackets in your regexp: String in = "John Doe (123456789)"; Pattern p = Pattern.compile

how to remove brackets character in string (java)

試著忘記壹切 提交于 2019-11-27 18:02:27
问题 I want to remove all type of brackets character (example: [],(),{}) in string by using java. I tried using this code: String test = "watching tv (at home)"; test = test.replaceAll("(",""); test = test.replaceAll(")",""); But it's not working, help me please. 回答1: To remove all punctuation marks that include all brackets, braces and sq. brackets ... as per the question is: String test = "watching tv (at home)"; test = test.replaceAll("\\p{P}",""); 回答2: The first argument of replaceAll takes a

Tournament bracket placement algorithm

我的未来我决定 提交于 2019-11-27 17:32:28
Given a list of opponent seeds (for example seeds 1 to 16), I'm trying to write an algorithm that will result in the top seed playing the lowest seed in that round, the 2nd seed playing the 2nd-lowest seed, etc. Grouping 1 and 16, 2 and 15, etc. into "matches" is fairly easy, but I also need to make sure that the higher seed will play the lower seed in subsequent rounds. An example bracket with the correct placement: 1 vs 16 1 vs 8 8 vs 9 1 vs 4 4 vs 13 4 vs 5 5 vs 12 1 vs 2 2 vs 15 2 vs 7 7 vs 10 2 vs 3 3 vs 14 3 vs 6 6 vs 11 As you can see, seed 1 and 2 only meet up in the final. This

How to use double brackets in a regular expression?

不问归期 提交于 2019-11-27 16:04:25
What do double square brackets mean in a regex? I am confused about the following examples: /[[^abc]]/ /[^abc]/ I was testing using Rubular , but I didn't see any difference between the one with double brackets and single brackets. Posix character classes use a [:alpha:] notation, which are used inside a regular expression like: /[[:alpha:][:digit:]]/ You'll need to scroll down a ways to get to the Posix information in the link above. From the docs: POSIX bracket expressions are also similar to character classes. They provide a portable alternative to the above, with the added benefit that

what is [] brackets in .net? [duplicate]

北城余情 提交于 2019-11-27 13:11:51
This question already has an answer here: All possible array initialization syntaxes 13 answers i have seen [] such brackets in c# very very rarely but when i start to learn asp.net i have seen them many times but still i couldn't understand what they does ? They are not part of code as using for arrays.For example [webmethods] which is just over the methods or there are some over classes. Are they part of .net or they are just tell something to CLR ? or ? Jouke van der Maas They are used to put Attributes on classes or methods (or other stuff). That way, you can attach data to classes that

issue with brackets in jQuery Form Data when sending data as json

半腔热情 提交于 2019-11-27 12:59:23
问题 I have the object var dataformdata={"key1":"value1","key2":"value2"}; then I add some more values with the same key(key3) like this dataformdata.key3 = []; dataformdata.key3.push("value3"); dataformdata.key3.push("value4"); I do the above in an each slope. It all works except when sending the dataformdata object via the jQuery ajax function in the browser console I see that there are brackets in the key ... $.ajax({ type: "POST", url: "/", data: dataformdata, ... This is what I see in the

[: missing `]' in bash script

夙愿已清 提交于 2019-11-27 08:45:43
问题 So I'm writing a bash shell script, and my first few lines looks like this: if ! [ $# -eq 0 || $# -eq 1 ]; then echo -e "Usage: myScriptName [\e[3mdir\e[0m] [\e[3m-f file\e[0m]" exit 1 fi But when I run it, it says "[: missing `]'". I don't see a missing ], and nothing except the ; is touching the ], so what am I missing? 回答1: You cannot use operators like || within single-brace test expressions. You must either do ! [[ $# -eq 0 || $# -eq 1 ]] or ! { [ $# -eq 0 ] || [ $# -eq 1 ]; } or ! [ $#