batch-rename

I have a bunch of files named like so: output_1.png output_2.png ... output_10.png ... output_120.png What is the easiest way of renaming those to match a convention, e.g. with maximum four decimals, so that the files are named: output_0001.png output_0002.png ... output_0010.png output_0120.png This should be easy in Unix/Linux/BSD, although I also have access to Windows. Any language is fine, but I'm interested in some really neat one-liners (if there are any?). DTing Python import os path = '/path/to/files/' for filename in os.listdir(path): prefix, num = filename[:-4].split('_') num = num

Is there any way of batch renaming files in sub directories? For example: Rename *.html to *.htm in a folder which has directories and sub directories. Anonymous Windows command prompt: (If inside a batch file, change %x to %%x) for /r %x in (*.html) do ren "%x" *.htm This also works for renaming the middle of the files for /r %x in (website*.html) do ren "%x" site*.htm For windows, this is the best tool I've found: http://www.1-4a.com/rename/ It can do anything AND has the kitchen sink with it. For Linux, you have a plethora of scripting languages and shells to help you, like the previous

I like to create a batch file (winxp cmd) that recursively goes through a chose folder and sub folders and renames there files+folders with the following rules: from all file + folder names, all uppercase+lowercase "V" and "W" letters need to be replaced with letters "Y" and "Z". e.g. 11V0W must become 11Y0Z. I believe its possible with FOR /R but how? I think there needs to be a subroutine to be called that checks each letter one by one in addition to basic recursion with FOR /R. The following batch does this for the file names at least. Directories are a bit trickier (at least I couldn't

Is there an easy way to rename a group of files already contained in a directory, using Python? Example: I have a directory full of *.doc files and I want to rename them in a consistent way. X.doc -> "new(X).doc" Y.doc -> "new(Y).doc" Such renaming is quite easy, for example with os and glob modules: import glob, os def rename(dir, pattern, titlePattern): for pathAndFilename in glob.iglob(os.path.join(dir, pattern)): title, ext = os.path.splitext(os.path.basename(pathAndFilename)) os.rename(pathAndFilename, os.path.join(dir, titlePattern % title + ext)) You could then use it in your example

I want to rename the files in a directory to sequential numbers. Based on creation date of the files. For Example sadf.jpg to 0001.jpg , wrjr3.jpg to 0002.jpg and so on, the number of leading zeroes depending on the total amount of files (no need for extra zeroes if not needed). Try to use a loop, let , and printf for the padding: a=1 for i in *.jpg; do new=$(printf "%04d.jpg" "$a") #04 pad to length of 4 mv -i -- "$i" "$new" let a=a+1 done using the -i flag prevents automatically overwriting existing files. Beauty in one line: ls -v | cat -n | while read n f; do mv -n "$f" "$n.ext"; done You