batch-rename

I have a large folder of .cbr's, and I'm renaming them by issue number to correctly order them. What do I need to include in the ren line to have each file increment the number in the file name via windows command prompt? I'll be doing this frequently so I'll make this a .bat file. For example, where n = initial number and m = final number: n.cbr, (n+1).cbr, ..., (m-1).cbr, m.cbr The .bat thusfar: ren *.cbz *.cbr ren *.cbr <increment numbers n through m>.cbr Alternatively, how do I trim each file name so that only the numbers are left before the extension? (from issue1.cbr to 1.cbr) via either

I have several folders with different images sharing file names, with a folder structure like this: /parent/folder001/img001.jpg /parent/folder001/img002.jpg /parent/folder002/img001.jpg /parent/folder002/img002.jpg /parent/folder003/img001.jpg /parent/folder003/img002.jpg ... and would like to copy/rename these files into a new folder, like this: /newfolder/folder001_img001.jpg /newfolder/folder001_img002.jpg /newfolder/folder002_img001.jpg /newfolder/folder002_img002.jpg /newfolder/folder003_img001.jpg /newfolder/folder003_img002.jpg ... (It's probably better if newfolder isn't a subfolder

I know there are a lot of things like this around, but either they don't work recursively or they are huge. This is what I got: find . -name "*.so" -exec mv {} `echo {} | sed s/.so/.dylib/` \; When I just run the find part it gives me a list of files. When I run the sed part it replaces any .so with .dylib. When I run them together they don't work. I replaced mv with echo to see what happened: ./AI/Interfaces/C/0.1/libAIInterface.so ./AI/Interfaces/C/0.1/libAIInterface.so Nothing is replaced at all! What is wrong? aps2012 This will do everything correctly : find -L . -type f -name "*.so"

I need to copy a file x.dtsx from location a to location b. If x.dtsx already exists in b then I need to rename x.dtsx to x_Standby.dtsx Then, after renaming copy x.dtsx to b My current code looks like this: if exists %1 rename %1 %(should be 1_standy.extension) xcopy %1 %2 If you use the Command Processor Extensions (which is default on Windows 2000 and later) then you can use the following optional syntax: %~1 - expands %1 removing any surrounding quotes (") %~f1 - expands %1 to a fully qualified path name %~d1 - expands %1 to a drive letter only %~p1 - expands %1 to a path only %~n1 -

I have something like this: v_1/file.txt v_2/file.txt v_3/file.txt ... and I want to rename those files to something like this: v_1.txt v_2.txt v_3.txt ... in the same directory. I guess I can use rename but I can't figure out how to use it with folder and file renaming at the same time. Csq The result can be achieved with a bash for loop and mv : for subdir in *; do mv $subdir/file.txt $subdir.txt; done; Note that the solution above will not work if the directory name contains spaces. Related link . Another solution based on comments (that works for directories having spaces in the name as

I need some help with a bash script. Script needs to rename all files in a directory to its md5 sum + extension. I have found the bash script below, but it needs to be changed so that it will add the extension. md5sum * | sed 's/^\(\w*\)\s*\(.*\)/\2 \1/' | while read LINE; do mv $LINE; done This might work for you: # mkdir temp && cd temp && touch file.{a..e} # ls file.a file.b file.c file.d file.e # md5sum * | sed -e 's/\([^ ]*\) \(.*\(\..*\)\)$/mv -v \2 \1\3/' | sh `file.a' -> `d41d8cd98f00b204e9800998ecf8427e.a' `file.b' -> `d41d8cd98f00b204e9800998ecf8427e.b' `file.c' ->