base-conversion

问题 I'm trying to make a function to convert decimal to balanced Heptavintimal (0123456789ABCDEFGHKMNPRTVXZ) where 0 represent -13, D : 0 and Z 13 I have tried this but some cases are not working properly: static const std::string HEPT_CHARS = "0123456789ABCDEFGHKMNPRTVXZ"; std::string heptEnc(int value){ std::string result = ""; do { int pos = value % 27; result = std::string(HEPT_CHARS[(pos + 13)%27] + result); value = value / 27; } while (value != 0); return result; } Here is what I get in

问题 I need to convert a binary input into a decimal integer. I know how to go from a decimal to a binary: n = int(raw_input('enter a number: ')) print '{0:b}'.format(n) I need to go in the reverse direction. My professor said that when he checks our code, he is going to input 11001 , and he should get 25 back. I've looked through our notes, and I cannot figure out how to do this. Google and other internet resources haven't been much help either. The biggest problem is that we are not allowed to

问题 I need to convert a binary input into a decimal integer. I know how to go from a decimal to a binary: n = int(raw_input('enter a number: ')) print '{0:b}'.format(n) I need to go in the reverse direction. My professor said that when he checks our code, he is going to input 11001 , and he should get 25 back. I've looked through our notes, and I cannot figure out how to do this. Google and other internet resources haven't been much help either. The biggest problem is that we are not allowed to

问题 I need to convert a binary input into a decimal integer. I know how to go from a decimal to a binary: n = int(raw_input('enter a number: ')) print '{0:b}'.format(n) I need to go in the reverse direction. My professor said that when he checks our code, he is going to input 11001 , and he should get 25 back. I've looked through our notes, and I cannot figure out how to do this. Google and other internet resources haven't been much help either. The biggest problem is that we are not allowed to

问题 I have just recently started learning C. I wrote a very short program that converts between decimal and binary. I wanted to try and write a code that converts between decimal and any base (up until 36). However, my code just prints out garbage. #include <stdio.h> #include <string.h> void printBase(int n, int k, int i, char a[]) { int placeholder; if (n != 0) { //return n % 2 + 10 * printBinary(n / 2); placeholder=(char)(n%k); if(placeholder>=10) { a[i] = (char)(placeholder - 10) + 'A'; } else

问题 I was given a task to convert decimal input numbers and output its binary equivalent via an "array" using assembly. I've the code complete and working, trouble is it only accepts numbers 0-99 for conversion. Ideally, the program should be able to convert any number at least up to 255 decimal so that the code can be reusable for future practices where I might need to handle different 16 bit values within registers. I appreciate all advice given, the code is as follows: .model small .stack

问题 I am using a hash algorithm to create a primary key for a database table. I use the SHA-1 algorithm which is more than fine for my purposes. The database even ships an implementation for SHA-1. The function computing the hash is returning a hex value as 40 characters. Therefore I am storing the hex characters in a char(40) column. The table will have lots of rows, >= 200 Mio. rows which is why I am looking for less data intensive ways of storing the hash. 40 characters times ~200 Mio. rows

问题 I don't know how to convert a non terminating binary number(fraction) to decimal . Can anybody guide me how to do with an example? 回答1: if the binary number is a unterminated integer, it would be infinite (positive or negative). How can you represent infinite number in decimal? I think it's ∞ . else if the binary number is a float-point number, congratulations. In many standard of float-point number(e.g., IEEE 754), the mantissa is represented by a binary pattern in which the highest bit has

问题 I am trying to convert a decimal number for example -268427136 to binary and vice versa. If I try with windows Calc, binary notation for this number is: 1111111111111111111111111111111111110000000000000010000010000000 If I try bindec,decbin or base_convert: echo(decbin(-268427136)); Outputs: 11110000000000000010000010000000 Or echo(bindec('1111111111111111111111111111111111110000000000000010000010000000'); Outputs: 1.84467440734E+19 What could I use in php to achieve same result? 回答1: Your

问题 I need to print some data (a little bit strange formatted). I was writing it in PHP with if ($num%10==9) but it was impossible for me to get correct output. So take a look at this for example. We have x of files in folder. For this example x=36. X is always known. Output should look like this: 01 02 03 04 05 06 07 08 09 0a 0b 0c 0d 0e 0f 10 11 ... 19 1a ... 1f 20 ... 24 Sorry for the such a long "list" but I believe that you know what I need now. So, after each number which ends with 9 we