awk

问题 I have a bash command that outputs text in the following format: Header 1 - Point 1 - Point 2 Header 2 - Point 1 - Point 2 Header 3 -Point 1 - Point 2 ... I want to parse this text into an array, separating on the empty line so that array[0] for example contains: Header 1 - Point 1 - Point 2 And then I want to edit some of the data in the array if it satisfies certain conditions. I was looking at something like this Separate by blank lines in bash but I'm completely new to bash so I don't

问题 While going through a piece of code I saw the below command: grep "r" temp | awk '{FS=","; $0=$0} { print $1,$3}' temp file contain the pattern like: 1. r,1,5 2. r,4,5 3. ... I could not understand what does the statement $0=$0 mean in awk command. Can anyone explain what does it mean? 回答1: When you do $1=$1 (or any other assignment to a field) it causes record recompilation where $0 is rebuilt with every FS replaced with OFS but it does not change NF (unless there was no $1 previously and

问题 While going through a piece of code I saw the below command: grep "r" temp | awk '{FS=","; $0=$0} { print $1,$3}' temp file contain the pattern like: 1. r,1,5 2. r,4,5 3. ... I could not understand what does the statement $0=$0 mean in awk command. Can anyone explain what does it mean? 回答1: When you do $1=$1 (or any other assignment to a field) it causes record recompilation where $0 is rebuilt with every FS replaced with OFS but it does not change NF (unless there was no $1 previously and

问题 How do you add a column to the end of a CSV file with using a string in a variable? input.csv 2012-02-29,01:00:00,Manhattan,New York,234 2012-02-29,01:00:00,Manhattan,New York,843 2012-02-29,01:00:00,Manhattan,New York,472 2012-02-29,01:00:00,Manhattan,New York,516 output.csv 2012-02-29,01:00:00,Manhattan,New York,234,2012-02-29 16:13:00 2012-02-29,01:00:00,Manhattan,New York,843,2012-02-29 16:13:00 2012-02-29,01:00:00,Manhattan,New York,472,2012-02-29 16:13:00 2012-02-29,01:00:00,Manhattan

问题 I have a question. This is my input file. #!/bin/bash name="eq6" tmp=$(mktemp) || exit 1 for index in {1..2} do awk 'f;/hbonds_Other-SOL/{f=1}' "${name}_$index.ndx" > "$tmp" && mv "$tmp" "${name}_$index.ndx" done Is it possible do this only in awk? I don't want to call awk in every for loop. This is my input eq6_1.ndx 98536 98539 98542 98545 98548 [ hbonds_Other-SOL ] 8 9 76759 eq6_2.ndx 98542 98545 98548 [ hbonds_Other-SOL ] 8 9 65281 Expected output - print all lines from all files which

问题 I have a question. This is my input file. #!/bin/bash name="eq6" tmp=$(mktemp) || exit 1 for index in {1..2} do awk 'f;/hbonds_Other-SOL/{f=1}' "${name}_$index.ndx" > "$tmp" && mv "$tmp" "${name}_$index.ndx" done Is it possible do this only in awk? I don't want to call awk in every for loop. This is my input eq6_1.ndx 98536 98539 98542 98545 98548 [ hbonds_Other-SOL ] 8 9 76759 eq6_2.ndx 98542 98545 98548 [ hbonds_Other-SOL ] 8 9 65281 Expected output - print all lines from all files which

问题 I have 100s of files in a directory with the following naming convention. 00XYZCD042ABCDE20141002ABCDE.XML 00XYZCC011ABCDE20141002.TXT 00XYZCB165ABCDE20141002ABCDE.TXT 00XYZCB165ABCDE20141002ABCDE.CSV I want to rename these files using bash , awk , cut , sed , so that I get the output: XYZCD042.XML XYZCC011.TXT XYZCB165.TXT XYZCB165.CSV So basically, remove the first two 0s always, and then keep everything until ABCDE starts and then remove everything including ABCDE and keep the file

问题 I have 100s of files in a directory with the following naming convention. 00XYZCD042ABCDE20141002ABCDE.XML 00XYZCC011ABCDE20141002.TXT 00XYZCB165ABCDE20141002ABCDE.TXT 00XYZCB165ABCDE20141002ABCDE.CSV I want to rename these files using bash , awk , cut , sed , so that I get the output: XYZCD042.XML XYZCC011.TXT XYZCB165.TXT XYZCB165.CSV So basically, remove the first two 0s always, and then keep everything until ABCDE starts and then remove everything including ABCDE and keep the file

问题 I have two files: candidates.csv : id,value 1,123 4,1 2,5 50,5 blacklist.csv : 1 2 5 3 10 I'd like to remove all rows from candidates.csv in which the first column ( id ) has a value contained in blacklist.csv . id is always numeric. In this case I'd like my output to look like this: id,value 4,1 50,5 So far, my script for identifying the duplicate lines looks like this: cat candidates.csv | cut -d \, -f 1 | grep -f blacklist.csv -w This gives me the output 1 2 Now I somehow need to pipe this

问题 I have two files: candidates.csv : id,value 1,123 4,1 2,5 50,5 blacklist.csv : 1 2 5 3 10 I'd like to remove all rows from candidates.csv in which the first column ( id ) has a value contained in blacklist.csv . id is always numeric. In this case I'd like my output to look like this: id,value 4,1 50,5 So far, my script for identifying the duplicate lines looks like this: cat candidates.csv | cut -d \, -f 1 | grep -f blacklist.csv -w This gives me the output 1 2 Now I somehow need to pipe this