args

C# check if you have passed arguments or not

由 牧云@^-^@ 提交于 2019-11-30 04:35:20
I have this code: public static void Main(string[] args) { if (string.IsNullOrEmpty(args[0])) // Warning : Index was out of the bounds of the array { ComputeNoParam cptern = new ComputeNoParam(); cptern.ComputeWithoutParameters(); } else { ComputeParam cpter = new ComputeParam(); foreach (string s in args){...} } } Also tried if(args.Length==0) , but it still doesn't work. Basically I want to find out if the user called the program with arguments. If not the program will ask for input. How can I do this? Thanks in advance. if(args.Length==0) should work, args[0] requires at least one argument

Store Bash script arguments $@ in a variable

由 試著忘記壹切 提交于 2019-11-29 15:43:31
问题 How can I store $@ in a variable while keeping its properties? I want to obtain exactly the same behavior even if I use $@ or my own variable in all possible situations. The attempts below didn't work: args=$@ args2="$@" # the arguments are combined (see the last output paragraph) I tested them using the following line: s.sh A B=" " C s.sh #!/bin/bash args=$@ args2="$@" #args3 = ? - TODO echo $args echo $args2 echo $@ #echo $args3 echo echo "$args" echo "$args2" echo "$@" #echo "$args3" echo

accessing the $args array in powershell

由 瘦欲@ 提交于 2019-11-29 05:14:27
问题 I have a test powershell V2 script that looks like this: function test_args() { Write-Host "here's arg 0: $args[0]" Write-Host "here's arg 1: $args[1]" } test_args If I call this from the powershell command prompt I get this on the screen: here's arg[0]: [0] here's arg[1]: [1] Not quite what I wanted. It seems I have to copy $args[0] and $args[1] to new variables in the script before I can use them? If I do that I can access things fine. Is there a way to access the indexed $args in my code?

C# check if you have passed arguments or not

由 纵饮孤独 提交于 2019-11-29 01:44:56
问题 I have this code: public static void Main(string[] args) { if (string.IsNullOrEmpty(args[0])) // Warning : Index was out of the bounds of the array { ComputeNoParam cptern = new ComputeNoParam(); cptern.ComputeWithoutParameters(); } else { ComputeParam cpter = new ComputeParam(); foreach (string s in args){...} } } Also tried if(args.Length==0) , but it still doesn't work. Basically I want to find out if the user called the program with arguments. If not the program will ask for input. How

Parsing arguments to a Java command line program

由 狂风中的少年 提交于 2019-11-28 17:25:14
What if I wanted to parse this: java MyProgram -r opt1 -S opt2 arg1 arg2 arg3 arg4 --test -A opt3 And the result I want in my program is: regular Java args[] of size=4 org.apache.commons.cli.Options[] of size=3 org.apache.commons.cli.Options[] #2 of size=1 I would prefer to use Apache Commons CLI , but the documentation is a little unclear about the case I present above. Specifically, the documentation doesn't tell you how to handle options of the 3rd type I specify below: 1. options with a "-" char 2. options with a "--" char 3. options without any marker, or "bare args" I wish that Apache

Could you technically call the string[] anything in the main method?

由 不打扰是莪最后的温柔 提交于 2019-11-28 14:49:42
The header for the main method is public static void main (String[] args) Could you technically replace "args" with anything you want? Also, why is the parameter an array? ΦXocę 웃 Пepeúpa ツ args is just a name for the argument in a method. You can rename it to whatever you want. The JVM doesn't need to know what the argument is named ; only the type , String[] , is important. dont break the start point of the app static void main(String[] whateverYouNeed) You can rename it to any proper Java identifier. The application needs to be able to accept multiple command-line arguments. It doesn't

Issue with main arguments handling

由 ℡╲_俬逩灬. 提交于 2019-11-28 14:34:28
I can't compare main() arguments with const char* strings. Simple code for explaining: #include <stdio.h> int main(int argc, char *argv[]) { int i; if(argc>1) { for (i=1;i<argc;++i) { printf("arg[%d] is %s\n",i,argv[i]); if(argv[i]=="hello") printf(" arg[%d]==\"hello\"\n",i); else printf(" arg[%d]!=\"hello\"\n",i); } } return 0; } Simple compile g++ test.cpp . When I try execute it, I see next thing: >./a.out hello my friend arg[1] is hello arg[1]!="hello" arg[2] is my arg[2]!="hello" arg[3] is friend arg[3]!="hello" Whats wrong with my code? In this statement if(argv[i]=="hello") you compare

Swift function with args… pass to another function with args

由 点点圈 提交于 2019-11-27 16:14:49
问题 I have a simple problem. I tried search in many blogs about this question but all site return how function in swift work, but I need this case. My custom function is: func getLocalizeWithParams(args:CVarArgType...)->String { return NSString.localizedStringWithFormat(self, args); //error: Expected expression in list of expressions } How I do to pass my args to other system function with args? Thanks advance. 回答1: Similar as in (Objective-)C, you cannot pass a variable argument list directly to

Parsing arguments to a Java command line program

由 蓝咒 提交于 2019-11-27 10:26:15
问题 What if I wanted to parse this: java MyProgram -r opt1 -S opt2 arg1 arg2 arg3 arg4 --test -A opt3 And the result I want in my program is: regular Java args[] of size=4 org.apache.commons.cli.Options[] of size=3 org.apache.commons.cli.Options[] #2 of size=1 I would prefer to use Apache Commons CLI, but the documentation is a little unclear about the case I present above. Specifically, the documentation doesn't tell you how to handle options of the 3rd type I specify below: 1. options with a "-

Issue with main arguments handling

由 给你一囗甜甜゛ 提交于 2019-11-27 08:25:58
问题 I can't compare main() arguments with const char* strings. Simple code for explaining: #include <stdio.h> int main(int argc, char *argv[]) { int i; if(argc>1) { for (i=1;i<argc;++i) { printf("arg[%d] is %s\n",i,argv[i]); if(argv[i]=="hello") printf(" arg[%d]==\"hello\"\n",i); else printf(" arg[%d]!=\"hello\"\n",i); } } return 0; } Simple compile g++ test.cpp . When I try execute it, I see next thing: >./a.out hello my friend arg[1] is hello arg[1]!="hello" arg[2] is my arg[2]!="hello" arg[3]
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