args

I'm working in Java and the typical way you specify multiple args for a method is: public static void someMethod(String[] args) But, I've seen another way a few times, even in the standard Java library. I don't know how to refer to this in conversation, and googling is not of much help due to the characters being used. public static void someMethod(Object... args) I know this allows you to string a bunch or arguments into a method without knowing ahead of time exactly how many there might be, such as: someMethod(String arg1, String arg2, String arg3, ... etc How do you refer to this type of

When I pass in "$1000" through the command line and retrieve the string through args[0], it becomes "000". How can I maintain the full string in my java code? I guess you're using some kind of Unix system, as '$' is the variable symbol in bash & co. Try using single quotes (e.g. java MyClass '$1000' ) 来源： https://stackoverflow.com/questions/33353649/escape-dollar-sign-in-command-line-arguments

I have tree types of sub-functions: one without any parameters (arguments), second with one parameter third with multiple parameters (tuple) I am trying to pass that functions and its arguments to another function which sum results of all sub-functions and return the sum value. Parameters in that function should be: names of each sub-function as position arguments (*args) and arguments of each subfunction as key-value arguments (*kvargs). Example : def no_arg() def one_arg(a) def multiple_args(a, b, c, e, f) # execution of function_results_sum: function_results_sum( no_arg, one_arg, multiple

I got confused with how to use args.length, I have coded something here: public static void main(String[] args) { int [] a = new int[args.length]; for(int i = 0;i<args.length;i++) { System.out.print(a[i]); } } The printout is 0 no matter what value I put in command line arguments, I think I probably confused args.length with the args[0], could someone explain? Thank you. int array is initialized to zero (all members will be zero) by default, see 4.12.5. Initial Values of Variables : Each class variable, instance variable, or array component is initialized with a default value when it is

I have a pandas dataframe 'df' with two columns 'A' and 'B', I have a function with two arguments def myfunction(B, A): # do something here to get the result return result and I would like to apply it row-by-row to df using the 'apply' function df['C'] = df['B'].apply(myfunction, args=(df['A'],)) but I get the error ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all(). whats happening here, it seems it takes df['A'] as the whole series! not just the row entry from that series as required. I think you need: import pandas as pd df = pd

I've got the following and was wondering if the initial test is overkill: static void Main(string[] args) { if (args.Length == 0 || args == null) { //do X } else { //do Y } } in other words what I'm asking is are there possibilities of args.Length being zero, or args being null....or would just one of these conditions sufficed? Well, Main is defined to never ever ever ever be called with a null parameter. If it does somehow receive a null parameter, then your environment is so broken that all bets are off no matter what you do, so there's really nothing to be gained by checking for null . On

How can I store $@ in a variable while keeping its properties? I want to obtain exactly the same behavior even if I use $@ or my own variable in all possible situations. The attempts below didn't work: args=$@ args2="$@" # the arguments are combined (see the last output paragraph) I tested them using the following line: s.sh A B=" " C s.sh #!/bin/bash args=$@ args2="$@" #args3 = ? - TODO echo $args echo $args2 echo $@ #echo $args3 echo echo "$args" echo "$args2" echo "$@" #echo "$args3" echo java A $args java A $args2 java A $@ #java A $args3 echo java A "$args" java A "$args2" java A "$@"