args

I can send callback param(s) and it works perfectly as long as I am only sending some primitive types like String. But the same thing does not work for even the simplest POJO. PrimeFaces guide says that the RequestContext.addCallbackParam() method can handle POJOs and it coverts them into JSON. I don't know why it's not working in my case. Has anybody done that? Solution found! --------------------------------------------------------------------- I did some research and found the answer to this question. And the solution was to use some JSON library (right now I am using GSON) to convert Java

How would you run a command and pass some custom arguments with Flutter/Dart so they can then be accessed in the main() call such as: flutter run -device [my custom arg] So then I can access it with: void main(List<String> args) { print(args.toString()); } Thank you. There is no way to do that, because when you start an app on your device there are also no parameters that are passed. If this is for development, you can pass -t lib/my_alternate_main.dart to flutter run to easily switch between different settings where each alternate entry-point file calls the same application code with

How does it work under the hood? I don't understand the reason for the errors below: >>> def f(): ... yield 1,2 ... yield 3,4 ... >>> *f() File "<stdin>", line 1 *f() ^ SyntaxError: invalid syntax >>> zip(*f()) [(1, 3), (2, 4)] >>> zip(f()) [((1, 2),), ((3, 4),)] >>> *args = *f() File "<stdin>", line 1 *args = *f() ^ SyntaxError: invalid syntax The *iterable syntax is only supported in an argument list of a function call (and in function definitions). In Python 3.x, you can also use it on the left-hand side of an assignment, like this: [*args] = [1, 2, 3] Edit : Note that there are plans to

Closed . This question needs details or clarity . It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post . Closed 2 years ago . I would like to my function func(*args, **kwargs) return one dictionary which contains all arguments I gave to it. For example: func(arg1, arg2, arg3=value3, arg4=value4) should return one dictionary like this: {'arg1': value1, 'arg2': value2, 'arg3': value3, 'arg4': value4 } You can use locals() or vars() : def func(arg1, arg2, arg3=3, arg4=4): print(locals()) func(1, 2) # {'arg3': 3, 'arg4': 4,

This question already has answers here : Closed 8 years ago . Possible Duplicate: Python 'self' keyword Forgive me if this is an incredibly noobish question, but I never did understand self in Python. What does it do? And when I see things like def example(self, args): return self.something what do they do? I think I've seen args somewhere in a function too. Please explain in a simple way :P It sounds like you've stumbled onto the object oriented features of Python. self is a reference to an object. It's very close to the concept of this in many C-style languages. Check out this code: class

This is what I'm looking for: def __init__(self, *args): list_of_args = #magic Parent.__init__(self, list_of_args) I need to pass *args to a single array, so that: MyClass.__init__(a, b, c) == Parent.__init__([a, b, c]) Nothing too magic: def __init__(self, *args): Parent.__init__(self, list(args)) Inside of __init__ , the variable args is just a tuple with any arguments that were passed in. In fact you can probably just use Parent.__init__(self, args) unless you really need it to be a list. As a side note, using super() is preferable to Parent.__init__() . There is this piece of code that I