algorithm

问题 You can read this on Wikipedia: function merge_sort(list m) // Base case. A list of zero or one elements is sorted, by definition. if length(m) <= 1 return m // Recursive case. First, *divide* the list into equal-sized sublists. var list left, right var integer middle = length(m) / 2 for each x in m before middle add x to left for each x in m after or equal middle add x to right // Recursively sort both sublists left = merge_sort(left) right = merge_sort(right) // Then merge the now-sorted

问题 You can read this on Wikipedia: function merge_sort(list m) // Base case. A list of zero or one elements is sorted, by definition. if length(m) <= 1 return m // Recursive case. First, *divide* the list into equal-sized sublists. var list left, right var integer middle = length(m) / 2 for each x in m before middle add x to left for each x in m after or equal middle add x to right // Recursively sort both sublists left = merge_sort(left) right = merge_sort(right) // Then merge the now-sorted

问题 Is there something similar to the "populate" method in Mongodb and includes in rails where Document Id's that are associated with other documents can be populated instead of me having to iterate through each document and make a separate query. For instance let's say that I have a group document that has a collection called members. And each document in that collection corresponds to the ID of a User document. Is there any way to populate each one of those documents, without me actually making

问题 Given a parameter k for the number of boxes and n data points, is there anyway I can find or approximate k axis-aligned bounding rectangles that enclose all the points while keeping the sum of the area of the rectangles minimum? 回答1: One way is to directly write this as a mathematical optimization problem. A high-level optimization model can look like as follows: We first define the decision variables: r(k,c) = coordinates for k-th box (e.g. c={x,y,w,h}) continuous variable with appropriate

问题 I need to delete nested for loop in a function I created. My function receive an associative array and I return a new array based on certain properties in order to group messages to use later. For example, I have two schools, many students. So I group them based on gender and grade. I don't how to refactor this function because I don't know much about algorithms. It doesn't matter if my logic need be erased completely or need to be done again. I must delete the second for loop. Also, I can

问题 So, I am self teaching Data Structure and Algorithm. While solving some problems I came across following problem where I have to segregate odd and even nodes of linked list. http://www.geeksforgeeks.org/segregate-even-and-odd-elements-in-a-linked-list/ Following is the problem statement: Given a Linked List of integers, write a function to modify the linked list such that all even numbers appear before all the odd numbers in the modified linked list. Also, keep the order of even and odd

问题 return a or b or c or d; That statement returns either true or false in C++, and I know the reason for this. But I need a workaround so that I can return the first non-zero value via that return statement (or something similar) like it happens in Python . I am not looking for conditional statements as it looks untidy sometimes. Basically, can the following code be shortened via a macro or something else? int fun(int a, int b, int c, int d) { return a ? a : b ? b : c ? c : d; } 回答1: I would

问题 So, I am self teaching Data Structure and Algorithm. While solving some problems I came across following problem where I have to segregate odd and even nodes of linked list. http://www.geeksforgeeks.org/segregate-even-and-odd-elements-in-a-linked-list/ Following is the problem statement: Given a Linked List of integers, write a function to modify the linked list such that all even numbers appear before all the odd numbers in the modified linked list. Also, keep the order of even and odd

问题 Suppose I have a randint(A, B) function which generates a uniformly distributed random integer in the (inclusive) range [A, B] . For example, 1 <= randint(1, 10) <= 10 . How can I efficiently randomly generate 3 distinct integers within a certain range? This should be done with exactly 3 calls to randint(A, B) . I don't care which permutation of the three numbers I get; it can be random or have a defined order. I'm not just trying to find any algorithm to do this, but (within reason) the

问题 I'm trying to build a Javascript function that takes as an input: array of players e.g. ["player1","player2","player3","player4"] (probably only equal number of players) and dynamically creates an array for a tournament design based on the following rules: each player partners no more than once with the same player every player has an equal amount of total matches the outputs would be an array containing arrays of matches with four entries each e.g. [player1, player2, player3, player4] stands