I want to get the elements of an array of characters, but no success at all, the problem is that I only get the first and last element and nothing more, my code is:
void getcharacters(char *cad) { int l; int *i; l=strlen(cad); for (i=&cad[0];i<&cad[l];i++){ printf("%c\n",*cad); } } any help? Thanks
You are using the same character (*cad or cad[0]) for all printf's. What you need is to use the index to get the next char in each iteration. Also i needs to be a pointer to char:
void getcharacters(char *cad) { int l; char *i; l=strlen(cad); for (i=&cad[0];i<&cad[l];i++){ printf("%c\n", *i ); } } The size of an int can be as big as 4 x the size of a char, so when you do i++ you are actually skipping 3 chars.
Also, you print out *cad instead of *i.
To fix change i to char* and print *i instead of *cad
Why don't you iterate from first character to the last one and accessing them as array index
int i; int l=strlen(cad); for (i=0;i<l;i++) { printf("%c\n",cad[i]); } Other answers have told you why it plain doesn't work, I'm wonder why you're not just iterating until the null terminator?
void getcharacters(char *cad) { char *i; for (i = cad; *i; i++) { printf("%c\n",*i); } }