jQuery toggle CSS?

问题:

I want to toggle between CSS so when a user clicks the button (#user_button) it shows the menu (#user_options) and changes the CSS, and when the user clicks it again it goes back to normal. So far this is all I have:

$('#user_button').click( function() {     $('#user_options').toggle();     $("#user_button").css({             borderBottomLeftRadius: '0px',         borderBottomRightRadius: '0px'     });      return false; }); 

Can anybody help?

回答1:

$('#user_button').toggle(function () {     $("#user_button").css({borderBottomLeftRadius: "0px"}); }, function () {     $("#user_button").css({borderBottomLeftRadius: "5px"}); }); 

Using classes in this case would be better than setting the css directly though, look at the addClass and removeClass methods alecwh mentioned.

$('#user_button').toggle(function () {     $("#user_button").addClass("active"); }, function () {     $("#user_button").removeClass("active"); }); 

回答2:

I would use the toggleClass function in jQuery and define the CSS to the class e.g.

/* start of css */ #user_button.active {     border-bottom-right-radius: 5px;     border-bottom-left-radius: 5px;     -webkit-border-bottom-right-radius: 5px; /* user-agent specific */     -webkit-border-bottom-left-radius: 5px;     -moz-border-radius-bottomright: 5px;     -moz-border-radius-bottomleft: 5px; /* etc... */ } /* start of js */ $('#user_button').click(function() {     $('#user_options').toggle();     $(this).toggleClass('active');     return false; }) 

回答3:

You might want to use jQuery's .addClass and .removeClass commands, and create two different classes for the states. This, to me, would be the best practice way of doing it.

回答4:

The best option would be to set a class style in CSS like .showMenu and .hideMenu with the various styles inside. Then you can do something like

$("#user_button").addClass("showMenu");  

文章来源: jQuery toggle CSS?