ArrayAdapter<DummyContent.DummyItem> with android.R.layout.simple_list_item_activated_2

匿名 (未验证) 提交于 2019-12-03 01:45:01

问题:

I'm currently using the master / detail flow in my android application project. Now I would like to not only create a list with items with only one string. I'd like to change the standard DummyItem class to the following:

     /**      * A dummy item representing a piece of content.      */     public static class DummyItem {         public String id;         public String content;         public String subtext; //Added subtext variable here         public DummyItem(String id, String content, String subtext) {             this.id = id;             this.content = content;             this.subtext = subtext; //And here         }          @Override         public String toString() {             return content;         }     }

In the ItemListFragment class I'm having this line of code pre-defined for creating the adapter for the list:

    setListAdapter(new ArrayAdapter<DummyContent.DummyItem>(getActivity(),                     android.R.layout.simple_list_item_activated_1,                     android.R.id.text1,                     DummyContent.ITEMS));

But I would like to change the android.R.layout.simple_list_item_activated_1 to android.R.layout.simple_list_item_activated_2

while having android.R.id.text1 as content and android.R.id.text2 as my subtext-variable.

Is there a possibility to do this?

回答1:

Overwrite the getView() Method of the ArrayAdapter. Should be something like this:

@Override public View getView(int position, View convertView, ViewGroup parent) {      //super call to create / recycle the view     View view = super.getView(position, convertView, parent);      TextView textView1 = (TextView) view.findViewById(android.R.id.text1);     textView1.setText(getItem(position).getContent());      TextView textView2 = (TextView) view.findViewById(android.R.id.text2);     textView2.setText(getItem(position).getSubtext());      return view;  }

Here's some further reading about ListViews, including examples: http://www.vogella.com/tutorials/AndroidListView/article.html



标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!