Pointer to array of unknown bound? [duplicate]

问题:

This question already has an answer here:

• Why is function(char * array[]) a valid function definition but not (char (*array)[] in C? 4 answers

The following function declaration is accepted by gcc, but not accepted by g++.

void do_something(char (*)[]); 

The error given by g++ is:

error: parameter '<anonymous>' includes pointer to array of unknown bound 'char []' 

I believe that in C, the parameter is converted to char** which is why gcc accepts it fine.

Can I make g++ accept this function somehow?

See example: http://ideone.com/yqvqdB :)

Thanks!

回答1:

The GNU GCC compiler uses non-standard compilant to compile program. Add this flag -std=c99 or -std=iso9899:1999 to compile your program as a standard input and you will get an error.

In standard this will be always accepted as a pointer to an array, so you must provide the lenght of the array as it's required for pointers arithmitics.

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