Merge and Update Two Lists in C#

Question

I have two List<T> objects:

For example:

List 1:
ID, Value where Id is populated and value is blank and it contains say IDs from 1 to 10.
1,""
2,""
...
10,""

List 2:
ID, Value and other attributes all filled with values but this list is a subset of List 1 in terms of IDs. (e.g only 3 items)
2,67
4,90
5,98

What I want is a merged list 1, but with updated values. Does anyone have any good extension method which will do this or any elegent code to perform this operation. The final list should be:

ID, Value
1,""
2,67 //value from list 2
3,""
4,90
5,98
6,""
...
10,""

Answer 1

I would probably use a dictionary rather than a list:

    // sample data
    var original = new Dictionary<int, int?>();
    for (int i = 1; i <= 10; i++)
    {
        original.Add(i, null);
    }
    var updated = new Dictionary<int, int>();
    updated.Add(2, 67);
    updated.Add(4, 90);
    updated.Add(5, 98);
    updated.Add(11, 20); // add

    // merge
    foreach (var pair in updated)
    {
        original[pair.Key] = pair.Value;
    }

    // show results
    foreach (var pair in original.OrderBy(x => x.Key))
    {
        Console.WriteLine(pair.Key + ": " + pair.Value);
    }

If you are talking about properties of an object, it will be trickier, but still doable.

Answer 2

use linq: list1=list2.Union(list1);

Answer 3

This is O(m*n) but should do the job for arbitrary lists

        foreach (var record in List1)
        {
            var other = List2.FirstOrDefault(x => x.Key == record.Key);
            if(other != null) record.Value = other.Value;
        }

If the lists are guaranteed ordered, then it could be brought down to O(n) at the cost of more code. The algortihm would be

Current items start as head of each list
While items remain in both lists
  If the current item of list1 has lower key than list2  advance to next in list1
  else if the current item of list2 has lower key than list1  advance to next in list2
  else copy value from current list2 item into list1 item and advance both lists.

Answer 4

If you have both lists sorted by ID, you can use a variation of the classical merge algorithm:

int pos = 0;
foreach (var e in list2) {
  pos = list1.FindIndex(pos, x => x.Id==e.Id);
  list1[pos].Value = e.Value;
}

Note that this also requires list2 to be a strict subset of list1 in terms of ID (i.e. list1 really contains all ids of list2)

Of course you can also wrap this in an extension method

public static void UpdateWith<T>(this List<T> list1, List<T> list2) 
where T:SomeIdValueSupertype {
  int pos = 0;
  foreach (var e in list2) {
    pos = list1.FindIndex(pos, x => x.Id==e.Id);
    list1[pos].Value = e.Value;
  }
}

Answer 5

 private void btnSearch_Click(object sender, EventArgs e)
{
String searchBy = cmbSearchBy.Text.ToString();
String searchFor = txtSearchFor.Text.Trim();

var List3 = (from row in JobTitleDB.jobList
                         where (row.JID.ToString()+row.JobTitleName.ToString().ToLower()).Contains(searchFor.ToLower())
                         select row).ToList();
if (searchBy == "All")
            {
                dgJobTitles.DataSource = null;
                //dgJobTitles.DataSource = List1;
                //dgJobTitles.DataSource = List2;
                //dgJobTitles.DataSource = List1.Concat(List2);
                //dgJobTitles.DataSource = List1.Union(List2);
                dgJobTitles.DataSource = List3;
                //dgJobTitles.DataSource=List1.AddRange(List2);
            }
}

Answer 6

Dictionary<int, string> List1 = new Dictionary<int, string>();
List1.Add(1,"");
List1.Add(2,"");
List1.Add(3,"");
List1.Add(4,"");
List1.Add(5,"");
List1.Add(6,"");

Dictionary<int, string> List2 = new Dictionary<int, string>();
List2.Add(2, "two");
List2.Add(4, "four");
List2.Add(6, "six");

var Result = List1.Select(x => new KeyValuePair<int, string>(x.Key, List2.ContainsKey(x.Key) ? List2[x.Key] : x.Value)).ToList();