Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Example 1:
2 / \ 1 3 Input: [2,1,3] Output: true
Example 2:
5 / \ 1 4 / \ 3 6 Input: [5,1,4,null,null,3,6] Output: false Explanation: The root node's value is 5 but its right child's value is 4.Time: O(N)
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def isValidBST(self, root: TreeNode) -> bool:
import sys
right_bound = sys.maxsize
left_bound = -sys.maxsize - 1
return self.helper(root, left_bound, right_bound)
def helper(self, root, left_bound, right_bound):
if root is None:
return True
if root.val <= left_bound or root.val >= right_bound:
return False
return self.helper(root.left, left_bound, root.val) and self.helper(root.right, root.val, right_bound)