It might not be a bug, but I don't know what is going wrong. My first entry is repeated for str1 on 2nd iteration, and is same way from then. Only first iteration goes good.
#include <iostream>
#include <string>
using namespace std;
int main () {
cout << " \n Enter two words. \n " ;
char c = 'y';
string str;
string str1;
while (c == 'y'){
getline(cin,str);
getline (cin,str1);
cout << " \n\n str : " << str << " str1 : " << str1 ;
cout << " \n Continue ? \n " ;
cin >> c;
}
return 0;
}
The output is :
Enter two words. hello world this is mr str : hello world str1 : this is mr Continue ? y hello world str : str1 : hello world Continue ? n
Add
cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n' );
after your
cin >> c;
Consider the following input:
dog
cat
y
owl
fish
n
If we examine the characters that are present in the input stream individually, we'll see:
d o g \n c a t \n y \n o w l \n f i s h \n n \n
The first call to getline consumes dog\n; the second consumes cat\n, leaving this:
y \n o w l \n f i s h \n n \n
The first call to cin >> c consumes only y but not the subsequent newline, leaving this:
\n o w l \n f i s h \n n \n
Now, the fun begins: What happens during the next call to getline? Why it reads up to the next newline, of course. So the next call to getline returns an empty line, and leaves owl... in the input stream.
The solution, as I outlined above, is to consume the remainder of the (now useless) input line.
As rob says.
But an alternative fix that looks nicer:
// change
char c = 'y';
....
while (c == 'y'){
....
cin >> c;
// Into
std::string c = "y";
....
while (c == "y"){
....
std::getline(cin, c);
When dealing with manual user input you should be careful of using the >> operator as this will always leave the '\n' on the input. Which means you can either use a method that retrieves the '\n' character (getline()) or you can manually remove it afterwords (ignore()).
来源：https://stackoverflow.com/questions/11144834/is-this-a-bug-with-getline-or-am-i-doing-something-wrong-right-way-to-use-ge