How to provide Hibernate Search parameters when using Spring Boot?
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spring.datasource.driverClassName=org.postgresql.Driver
hibernate.search.jmx_enabled=true
hibernate.search.default.directory_provider=filesystem
hibernate.search.generate_statistics=true
hibernate.search.lucene_version=LUCENE_CURRENT
hibernate.search.default.indexBase=/mypath-to-index
It does not care what I provide. Default settings always get applied.
I think below code does not have anything to process properties related to Hibernate Search. Can that be the issue?
You can put them in the application.properties file if you put "spring.jpa.properties." in front of the property names.
Example:
spring.jpa.properties.hibernate.search.jmx_enabled=true
spring.jpa.properties.hibernate.search.default.directory_provider=filesystem
spring.jpa.properties.hibernate.search.generate_statistics=true
spring.jpa.properties.hibernate.search.lucene_version=LUCENE_CURRENT
spring.jpa.properties.hibernate.search.default.indexBase=/mypath-to-index
Spring will take any properties under spring.jpa.properties.* and pass them along (with the prefix stripped) once the EntityManagerFactory is created.
Got it working.
Put another property file named "hibernate.properties" inside src/main/resources with below content.
hibernate.search.jmx_enabled=true
hibernate.search.default.directory_provider=filesystem
hibernate.search.generate_statistics=true
hibernate.search.lucene_version=LUCENE_CURRENT
hibernate.search.default.indexBase=/mypath-to-index
来源:https://stackoverflow.com/questions/25474445/spring-boot-hibernate-search-properties