Upper limit in Python time.sleep()?

旧街凉风 提交于 2019-11-29 15:51:59

I suppose the longer the time the more probable situation described in the docs:

The actual suspension time may be less than that requested because any caught signal will terminate the sleep() following execution of that signal’s catching routine. Also, the suspension time may be longer than requested by an arbitrary amount because of the scheduling of other activity in the system.

Others have explained why you might sleep for less than you asked for, but didn't show you how to deal with this. If you need to make sure you sleep for at least n seconds you can use code like:

from time import time, sleep
def trusty_sleep(n):
    start = time()
    while (time() - start < n):
        sleep(n - (time() - start))

This may sleep more than n but it will never return before sleeping at least n seconds.

The spec says:

Suspend execution for the given number of seconds. The argument may be a floating point number to indicate a more precise sleep time. The actual suspension time may be less than that requested because any caught signal will terminate the sleep() following execution of that signal’s catching routine. Also, the suspension time may be longer than requested by an arbitrary amount because of the scheduling of other activity in the system.

Nothing about a time limit here. Certainly 1K seconds isn't much and should work without problems.

According to the documentation, time.sleep accepts any non-zero number [1], as you probably know. However you are under the influence of your operating systems scheduler as well [1].

[1] http://docs.python.org/library/time.html

you can prevent possible issues by putting the sleep with short delay into the loop:

def sleep(n):
    for i in xrange(n):
        time.sleep(1)

Actual answer, at least for my machine: 4294967.2950000003911900999... seconds.

sleep(4294967.2950000003911901)

OverflowError: sleep length is too large

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