I have a problem about variable in variable ( the code is below ) :
set a=1
set b=a
echo %%b%%
The expected result is :
1
As a is assigned to variable b and 1 is assigned to variable a.
Also, there is another situation :
set b=a
set a1=100
set c=1
call set d=%a%c%%
echo %d%
I want the program to first turn %c% to 1 and then turn %a1% to 100.
The expected output is 100.
What is the simplest way to complete this task?
set a=1
set b=a
call echo %%%b%%%
And this will work faster:
@echo off
set a=1
set b=a
setlocal enableDelayedExpansion
echo !%b%!
endlocal
And just in case you need to do this within brackets context (e.g. if , for ...) :
@echo off
set a=1
set b=a
setlocal enableDelayedExpansion
(
for /f %%v in ("%b%") do echo !%%~v!
)
endlocal
like for the variable x%abc%,
echo x%abc%>a.a
set /p temp=<a.a
call echo %%temp%%>a.a
set /p temp=<a.a
set temp
That's all!
来源:https://stackoverflow.com/questions/21278968/cmd-get-variable-in-variable-name