WPF invoke a control

落爺英雄遲暮 提交于 2019-11-29 09:24:31

When you call Invoke, you're not specifying your argument (text). When the Dispatcher tries to run your method, it doesn't have a parameter to supply, and you get an exception.

Try:

this.textboxlink.Dispatcher.Invoke(
     System.Windows.Threading.DispatcherPriority.Normal,
     new TBXTextChanger(this.WriteToTextBox), text);

If you want to read the value from a text box, one option is to use a lambda:

string textBoxValue = string.Empty;

this.textboxlink.Dispatcher.Invoke(DispatcherPriority.Normal, 
     new Action( () => { textBoxValue = this.textboxlink.Text; } ));

if (textBoxValue == string.Empty)
    Thread.Sleep(5000);

Reed is correct, but the reason you need to do this is that GUI elements are not thread safe and so all GUI operations have to be done on the GUI thread to ensure that the content is being read correctly. Its less obvious why this is necessary with a read operation like this but it is very necessary with writes and so the .NET framework just requires all access to the GUI to be done in the GUI thread.

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