问题
I am looking for the best way to \"add\" multiple JavaScript objects (associative arrays).
For example, given:
a = { \"one\" : 1, \"two\" : 2 };
b = { \"three\" : 3 };
c = { \"four\" : 4, \"five\" : 5 };
what is the best way to compute:
{ \"one\" : 1, \"two\" : 2, \"three\" : 3, \"four\" : 4, \"five\" : 5 }
回答1:
ECMAscript 6 introduced Object.assign() to achieve this natively in Javascript.
The Object.assign() method is used to copy the values of all enumerable own properties from one or more source objects to a target object. It will return the target object.
MDN documentation on Object.assign()
var o1 = { a: 1 };
var o2 = { b: 2 };
var o3 = { c: 3 };
var obj = Object.assign({}, o1, o2, o3);
console.log(obj); // { a: 1, b: 2, c: 3 }
Object.assign is supported in many modern browsers but not yet all of them. Use a transpiler like Babel and Traceur to generate backwards-compatible ES5 JavaScript.
回答2:
You could use jquery's $.extend like this:
let a = { "one" : 1, "two" : 2 },
b = { "three" : 3 },
c = { "four" : 4, "five" : 5 };
let d = $.extend({}, a, b, c)
console.log(d)
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
回答3:
This should do it:
function collect() {
var ret = {};
var len = arguments.length;
for (var i = 0; i < len; i++) {
for (p in arguments[i]) {
if (arguments[i].hasOwnProperty(p)) {
ret[p] = arguments[i][p];
}
}
}
return ret;
}
let a = { "one" : 1, "two" : 2 };
let b = { "three" : 3 };
let c = { "four" : 4, "five" : 5 };
let d = collect(a, b, c);
console.log(d);
Output:
{
"one": 1,
"two": 2,
"three": 3,
"four": 4,
"five": 5
}
回答4:
ECMAScript 6 has spread syntax. And now you can do this:
const obj1 = { 1: 11, 2: 22 };
const obj2 = { 3: 33, 4: 44 };
const obj3 = { ...obj1, ...obj2 };
console.log(obj3); // {1: 11, 2: 22, 3: 33, 4: 44}
回答5:
Underscore has few methods to do this;
1. _.extend(destination, *sources)
Copy all of the properties in the source objects over to the destination object, and return the destination object.
_.extend(a, _.extend(b, c));
=> {"one" : 1, "two" : 2, "three" : 3, "four" : 4, "five" : 5 }
Or
_.extend(a, b);
=> {"one" : 1, "two" : 2, "three" : 3}
_.extend(a, c);
=> {"one" : 1, "two" : 2, "three" : 3, "four" : 4, "five" : 5 }
2. _.defaults(object, *defaults)
Fill in undefined properties in object with values from the defaults objects, and return the object.
_.defaults(a, _.defaults(b, c));
=> {"one" : 1, "two" : 2, "three" : 3, "four" : 4, "five" : 5 }
Or
_.defaults(a, b);
=> {"one" : 1, "two" : 2, "three" : 3}
_.defaults(a, c);
=> {"one" : 1, "two" : 2, "three" : 3, "four" : 4, "five" : 5 }
回答6:
Why should the function be restricted to 3 arguments? Also, check for hasOwnProperty.
function Collect() {
var o={};
for(var i=0;i<arguments.length;i++) {
var arg=arguments[i];
if(typeof arg != "object") continue;
for(var p in arg) {
if(arg.hasOwnProperty(p)) o[p] = arg[p];
}
}
return o;
}
回答7:
function Collect(a, b, c) {
for (property in b)
a[property] = b[property];
for (property in c)
a[property] = c[property];
return a;
}
Notice: Existing properties in previous objects will be overwritten.
回答8:
Shallow-cloning (excluding prototype) or merging of objects is now possible using a shorter syntax than Object.assign().
Spread syntax for object literals was introduced in ECMAScript 2018):
const a = { "one": 1, "two": 2 };
const b = { "three": 3 };
const c = { "four": 4, "five": 5 };
const result = {...a, ...b, ...c};
// Object { "one": 1, "two": 2 , "three": 3, "four": 4, "five": 5 }
Spread (...) operator is supported in many modern browsers but not all of them.
So, it is recommend to use a transpiler like Babel to convert ECMAScript 2015+ code into a backwards compatible version of JavaScript in current and older browsers or environments.
This is the equivalent code Babel will generate for you:
"use strict";
var _extends = Object.assign || function(target) {
for (var i = 1; i < arguments.length; i++) {
var source = arguments[i];
for (var key in source) {
if (Object.prototype.hasOwnProperty.call(source, key)) {
target[key] = source[key];
}
}
}
return target;
};
var a = { "one": 1, "two": 2 };
var b = { "three": 3 };
var c = { "four": 4, "five": 5 };
var result = _extends({}, a, b, c);
// Object { "one": 1, "two": 2 , "three": 3, "four": 4, "five": 5 }
回答9:
Probably, the fastest, efficient and more generic way is this (you can merge any number of objects and even copy to the first one ->assign):
function object_merge(){
for (var i=1; i<arguments.length; i++)
for (var a in arguments[i])
arguments[0][a] = arguments[i][a];
return arguments[0];
}
It also allows you to modify the first object as it passed by reference. If you don't want this but want to have a completely new object containing all properties, then you can pass {} as the first argument.
var object1={a:1,b:2};
var object2={c:3,d:4};
var object3={d:5,e:6};
var combined_object=object_merge(object1,object2,object3);
combined_object and object1 both contain the properties of object1,object2,object3.
var object1={a:1,b:2};
var object2={c:3,d:4};
var object3={d:5,e:6};
var combined_object=object_merge({},object1,object2,object3);
In this case, the combined_object contains the properties of object1,object2,object3 but object1 is not modified.
Check here: https://jsfiddle.net/ppwovxey/1/
Note: JavaScript objects are passed by reference.
回答10:
Simplest: spread operators
var obj1 = {a: 1}
var obj2 = {b: 2}
var concat = { ...obj1, ...obj2 } // { a: 1, b: 2 }
回答11:
ES6 ++
The question is adding various different objects into one.
let obj = {};
const obj1 = { foo: 'bar' };
const obj2 = { bar: 'foo' };
Object.assign(obj, obj1, obj2);
//output => {foo: 'bar', bar: 'foo'};
lets say you have one object with multiple keys that are objects:
let obj = {
foo: { bar: 'foo' },
bar: { foo: 'bar' }
}
this was the solution I found (still have to foreach :/)
let objAll = {};
Object.values(obj).forEach(o => {
objAll = {...objAll, ...o};
});
By doing this we can dynamically add ALL object keys into one.
// Output => { bar: 'foo', foo: 'bar' }
回答12:
function collect(a, b, c){
var d = {};
for(p in a){
d[p] = a[p];
}
for(p in b){
d[p] = b[p];
}
for(p in c){
d[p] = c[p];
}
return d;
}
来源:https://stackoverflow.com/questions/2454295/how-to-concatenate-properties-from-multiple-javascript-objects