I would like to send email through a proxy.
My current implementation is as follows:
I connect to the smtp server with authentication. After I've successfully logged in, I send an email. It works fine but when I look at the email header I can see my host name. I would like to tunnel it through a proxy instead.
Any help will be highly appreciated.
aivarsk
Use SocksiPy:
import smtplib
import socks
#'proxy_port' should be an integer
#'PROXY_TYPE_SOCKS4' can be replaced to HTTP or PROXY_TYPE_SOCKS5
socks.setdefaultproxy(socks.PROXY_TYPE_SOCKS4, proxy_host, proxy_port)
socks.wrapmodule(smtplib)
smtp = smtplib.SMTP()
...
I had a similar problem yesterday, this is the code I wrote to solve the problem. It invisibly allows you to use all of the smtp methods via proxy.
#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
# smtprox.py
# Shouts to suidrewt
#
# ############################################# #
# This module allows Proxy support in MailFux. #
# Shouts to Betrayed for telling me about #
# http CONNECT #
# ############################################# #
import smtplib
import socket
def recvline(sock):
stop = 0
line = ''
while True:
i = sock.recv(1)
if i == '\n': stop = 1
line += i
if stop == 1:
break
return line
class ProxSMTP( smtplib.SMTP ):
def __init__(self, host='', port=0, p_address='',p_port=0, local_hostname=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
"""Initialize a new instance.
If specified, `host' is the name of the remote host to which to
connect. If specified, `port' specifies the port to which to connect.
By default, smtplib.SMTP_PORT is used. An SMTPConnectError is raised
if the specified `host' doesn't respond correctly. If specified,
`local_hostname` is used as the FQDN of the local host. By default,
the local hostname is found using socket.getfqdn().
"""
self.p_address = p_address
self.p_port = p_port
self.timeout = timeout
self.esmtp_features = {}
self.default_port = smtplib.SMTP_PORT
if host:
(code, msg) = self.connect(host, port)
if code != 220:
raise SMTPConnectError(code, msg)
if local_hostname is not None:
self.local_hostname = local_hostname
else:
# RFC 2821 says we should use the fqdn in the EHLO/HELO verb, and
# if that can't be calculated, that we should use a domain literal
# instead (essentially an encoded IP address like [A.B.C.D]).
fqdn = socket.getfqdn()
if '.' in fqdn:
self.local_hostname = fqdn
else:
# We can't find an fqdn hostname, so use a domain literal
addr = '127.0.0.1'
try:
addr = socket.gethostbyname(socket.gethostname())
except socket.gaierror:
pass
self.local_hostname = '[%s]' % addr
smtplib.SMTP.__init__(self)
def _get_socket(self, port, host, timeout):
# This makes it simpler for SMTP_SSL to use the SMTP connect code
# and just alter the socket connection bit.
if self.debuglevel > 0: print>>stderr, 'connect:', (host, port)
new_socket = socket.create_connection((self.p_address,self.p_port), timeout)
new_socket.sendall("CONNECT {0}:{1} HTTP/1.1\r\n\r\n".format(port,host))
for x in xrange(2): recvline(new_socket)
return new_socket
This code has earned from me. 1. The file name must not be email.py Rename file name for example emailSend.py 2. It is necessary to allow Google to send messages from unreliable sources.
The smtplib module doesn't include the functionality to connect to a SMTP server through a HTTP proxy. The custom class posted by ryoh didn't work for me, apparently because my HTTP proxy receives encoded messages only. I wrote the following custom class based on ryos's code, and it worked fine. (Your mileage, however, may vary.)
import smtplib
import socket
def recvline(sock):
"""Receives a line."""
stop = 0
line = ''
while True:
i = sock.recv(1)
if i.decode('UTF-8') == '\n': stop = 1
line += i.decode('UTF-8')
if stop == 1:
print('Stop reached.')
break
print('Received line: %s' % line)
return line
class ProxySMTP(smtplib.SMTP):
"""Connects to a SMTP server through a HTTP proxy."""
def __init__(self, host='', port=0, p_address='',p_port=0, local_hostname=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
"""Initialize a new instance.
If specified, `host' is the name of the remote host to which to
connect. If specified, `port' specifies the port to which to connect.
By default, smtplib.SMTP_PORT is used. An SMTPConnectError is raised
if the specified `host' doesn't respond correctly. If specified,
`local_hostname` is used as the FQDN of the local host. By default,
the local hostname is found using socket.getfqdn().
"""
self.p_address = p_address
self.p_port = p_port
self.timeout = timeout
self.esmtp_features = {}
self.default_port = smtplib.SMTP_PORT
if host:
(code, msg) = self.connect(host, port)
if code != 220:
raise IOError(code, msg)
if local_hostname is not None:
self.local_hostname = local_hostname
else:
# RFC 2821 says we should use the fqdn in the EHLO/HELO verb, and
# if that can't be calculated, that we should use a domain literal
# instead (essentially an encoded IP address like [A.B.C.D]).
fqdn = socket.getfqdn()
if '.' in fqdn:
self.local_hostname = fqdn
else:
# We can't find an fqdn hostname, so use a domain literal
addr = '127.0.0.1'
try:
addr = socket.gethostbyname(socket.gethostname())
except socket.gaierror:
pass
self.local_hostname = '[%s]' % addr
smtplib.SMTP.__init__(self)
def _get_socket(self, port, host, timeout):
# This makes it simpler for SMTP to use the SMTP connect code
# and just alter the socket connection bit.
print('Will connect to:', (host, port))
print('Connect to proxy.')
new_socket = socket.create_connection((self.p_address,self.p_port), timeout)
s = "CONNECT %s:%s HTTP/1.1\r\n\r\n" % (port,host)
s = s.encode('UTF-8')
new_socket.sendall(s)
print('Sent CONNECT. Receiving lines.')
for x in range(2): recvline(new_socket)
print('Connected.')
return new_socket
To connect to the SMTP server, just use the class ProxySMTP instead of smtplib.SMTP.
proxy_host = YOUR_PROXY_HOST
proxy_port = YOUR_PROXY_PORT
# Both port 25 and 587 work for SMTP
conn = ProxySMTP(host='smtp.gmail.com', port=587,
p_address=proxy_host, p_port=proxy_port)
conn.ehlo()
conn.starttls()
conn.ehlo()
r, d = conn.login(YOUR_EMAIL_ADDRESS, YOUR_PASSWORD)
print('Login reply: %s' % r)
sender = 'from@fromdomain.com'
receivers = ['to@todomain.com']
message = """From: From Person <from@fromdomain.com>
To: To Person <to@todomain.com>
Subject: SMTP e-mail test
This is a test e-mail message.
"""
print('Send email.')
conn.sendmail(sender, receivers, message)
print('Success.')
conn.close()
来源：https://stackoverflow.com/questions/5239797/python-smtplib-proxy-support