Difference between openjdk-6-jre, openjdk-6-jre-headless, openjdk-6-jre-lib

Question

I am having trouble understanding some of the basics of Java JRE.

I need to run Java code in an embedded system and for this I need a minimal Java Runtime Environment installed in a Linux kernel, that is to say, the minimum package necessary for executing Java binaries. I think it is not possible to do this only with a JVM (the JRE package is necessary, am I wrong here?)

The thing is, when looking at the Debian repositories I don't quite understand the differences between the packages openjdk-6-jre, openjdk-6-jre-headless and openjdk-6-jre-lib. Will Java programs run only with the former? or, are the three of them needed?

This is an issue as there is a big difference in size (MB) between them.

Answer 1

You are correct in that you will need a jre package to run any java application.

Since you say you're running on an embedded platform I assume that the java app you want to run has no gui. In that case, you will be fine with openjdk-6-jre-headless. This is explained on the openjdk-6-jre-headless package page here "Minimal Java runtime - needed for executing non GUI Java programs".

As you can see from the debian package details page, openjdk-6-jre-headless depends on openjdk-6-jre-lib (among other packages), so that will get installed either way.

If however the java app you want to run has a gui, you will need openjdk-6-jre instead of openjdk-6-jre-headless

Edit: Fixed links.

Edit: Fixed Links again

Answer 2

The main reason for having two distinct packages available are the dependencies of the packages. openjdk-6-jre will also depend on:

libasound2, libgif4, libjpeg62, libpng12-0, libpulse0 , libx11-6, libxext6, libxi6, libxrender1, libxtst6 and zlib1g

And contrary to the previous comment openjdk-6-jre depends on openjdk-6-jre-headless, making the latter really just a subset.