问题
I have a flat structured XML file as below:
<rs>
<r id="r1" lev="0"/>
<r id="r2" lev="1"/>
<r id="r3" lev="0"/>
<r id="r4" lev="1"/>
<r id="r5" lev="2"/>
<r id="r6" lev="3"/>
<r id="r7" lev="0"/>
<r id="r8" lev="1"/>
<r id="r9" lev="2"/>
</rs>
which I need to transform to a nested one. Rule is something, all r[number(@lev) gt 0] should be nested within r[number(@lev) eq 0]. And the output would be something like that:
<rs>
<r id="r1">
<r id="r2"/>
</r>
<r id="r3">
<r id="r4">
<r id="r5">
<r id="r6"/>
</r>
</r>
</r>
<r id="r7">
<r id="r8">
<r id="r9"/>
</r>
</r>
</rs>
What I have tried is the following transformation:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<rs>
<xsl:apply-templates select="node()|@*"/>
</rs>
</xsl:template>
<xsl:template match="r">
<xsl:variable name="lev" select="number(@lev)" as="xs:double"/>
<r>
<xsl:copy-of select="@id"/>
<xsl:apply-templates select="following-sibling::r[not(number(@lev) eq $lev)
and
count(preceding-sibling::r[number(@lev) eq $lev]) eq 1]"/>
</r>
</xsl:template>
</xsl:stylesheet>
But, this does not gives me the desired result. Pointing out my coding error or any other approach to get job done, is greatly appreciated.
回答1:
Dimitre tends to give answers to questions using XSLT 1.0 unless otherwise requested. That may be a correct guess, but I think it's worth pointing out that XSLT 2.0 is now quite widely available and used, and that the code for grouping problems in XSLT 2.0 is much simpler (it may not always be much shorter, but it is much more readable). Unlike Dimitre, I don't have the time or inclination to give beautiful complete and tested solutions to every question, but if you want to see an XSLT 2.0 solution to this problem there is one in a paper I wrote some years ago here:
http://www.saxonica.com/papers/ideadb-1.1/mhk-paper.xml
Search for the recursive template name="process-level".
回答2:
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:key name="kRByLevelAndParent" match="r"
use="concat(generate-id(preceding-sibling::r
[not(@lev >= current()/@lev)][1]),
@lev
)"/>
<xsl:template match="/*">
<rs>
<xsl:apply-templates select="key('kRByLevelAndParent', '0')"/>
</rs>
</xsl:template>
<xsl:template match="r">
<r id="{@id}">
<xsl:apply-templates select=
"key('kRByLevelAndParent',
concat(generate-id(), @lev+1)
)"/>
</r>
</xsl:template>
</xsl:stylesheet>
when applied on the provided XML document:
<rs>
<r id="r1" lev="0"/>
<r id="r2" lev="1"/>
<r id="r3" lev="0"/>
<r id="r4" lev="1"/>
<r id="r5" lev="2"/>
<r id="r6" lev="3"/>
<r id="r7" lev="0"/>
<r id="r8" lev="1"/>
<r id="r9" lev="2"/>
</rs>
produces the wanted, correct result:
<rs>
<r id="r1">
<r id="r2"/>
</r>
<r id="r3">
<r id="r4">
<r id="r5">
<r id="r6"/>
</r>
</r>
</r>
<r id="r7">
<r id="r8">
<r id="r9"/>
</r>
</r>
</rs>
Explanation:
Positional grouping using a composite key -- for all its "children" an element is the first preceding sibling such that its lev attribute is less than their respective lev attribute.
回答3:
As I need to apply the transformation within temporary variables, using xsl:key would not help. And if I have to use Dimitre's solution I had to change my existing code.
And obviously it was my mistake that I have not describe much in this regard in my question.
From the link at //programlisting[contains(.,'xsl:template name="process-level"')] provided by Dr. Kay I have concluded the solution, may be some other person could be use it later:
The stylesheet
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs">
<xsl:output indent="yes"/>
<xsl:template match="/*">
<rs>
<xsl:call-template name="process-level">
<xsl:with-param name="context"
select="r"/>
<xsl:with-param name="level"
select="0"/>
</xsl:call-template>
</rs>
</xsl:template>
<xsl:template name="process-level">
<xsl:param name="context" required="yes" as="element()*"/>
<xsl:param name="level" as="xs:double"/>
<xsl:for-each-group select="$context"
group-starting-with="*[number(@lev) eq $level]">
<xsl:element name="{name()}">
<!--<xsl:variable name="position" as="xs:double">
<xsl:number level="any" count="*[starts-with(local-name(), 'r')]"/>
</xsl:variable>-->
<xsl:copy-of select="@id"/>
<xsl:call-template name="process-level">
<xsl:with-param name="context" select="current-group()[position() != 1]"/>
<xsl:with-param name="level" select="$level + 1"/>
</xsl:call-template>
</xsl:element>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
The input XML
<rs>
<r id="r1" lev="0"/>
<r id="r2" lev="1"/>
<r id="r3" lev="0"/>
<r id="r4" lev="1"/>
<r id="r5" lev="2"/>
<r id="r6" lev="3"/>
<r id="r7" lev="0"/>
<r id="r8" lev="1"/>
<r id="r9" lev="2"/>
</rs>
And the result
<rs>
<r id="r1">
<r id="r2"/>
</r>
<r id="r3">
<r id="r4">
<r id="r5">
<r id="r6"/>
</r>
</r>
</r>
<r id="r7">
<r id="r8">
<r id="r9"/>
</r>
</r>
</rs>
来源：https://stackoverflow.com/questions/11113161/flat-to-nested-structure-based-on-attribute-value-using-xslt