Convert SVG to transparent PNG with antialiasing, using ImageMagick

Question

I want to convert SVG images to PNG files with transparent background and anti-aliased edges (using semi-transparent pixels). Unfortunately I can't get ImageMagick to do the anti-aliasing, the edges always look terrible. Here's what I tried:

convert +antialias -background transparent  in.svg -resize 25x25 out.png

Any ideas or a different command line tool I could use?

Answer 1

Inkscape will do this:

inkscape \
    --export-png=out.png --export-dpi=200 \
    --export-background-opacity=0 --without-gui in.svg

Answer 2

As a side note, I found that getting transparency was a bit tricky. Instead of using transparent, I had to use none.

convert -background none in.svg out.png

Answer 3

Actually, reading imagemagick documentation:

-antialias

Enable/Disable of the rendering of anti-aliasing pixels when drawing fonts and lines. By default, objects (e.g. text, lines, polygons, etc.) are antialiased when drawn. Use +antialias to disable the addition of antialiasing edge pixels. This will then reduce the
number of colors added to an image to just the colors being directly drawn. That is, no mixed >colors are added when drawing such objects.

the +antialias will indeed disable antialiasing.

Answer 4

The way I learned how to do this was from the methodology found here: How to convert a .eps file to a high quality 1024x1024 .jpg?

It is the same idea as @halfer's solution with inkscape--to jack up the DPI first--but you can accomplish the same thing in just imagemagick using the -density option.

convert -density 200 in.svg -resize 25x25 -transparent white out.png

Answer 5

Adding the -transparent white option solves the problem particularly in my case because background isn't removed completely (unfortunately light shadow is present). So I'm using IMHO more clearer solution that fully removes background with ImageMagic:

convert -channel rgba -background "rgba(0,0,0,0)" in.svg out.png

It sets a fully transparent black color as the background through the RGBA channel.

Answer 6

I add a rect as background. The embed CSS hide the background. Then I catch its color for setting the transparent attribute of ImageMagick.

---

SVG file:

<?xml version="1.0" ?>
<!DOCTYPE svg  PUBLIC '-//W3C//DTD SVG 1.1//EN'  'http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd'>
<svg 
    version="1.1" xml:space="preserve" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"
    width="500px" height="500px"
    viewBox="0 0 500 500" 
    enable-background="new 0 0 500 500" 
    >
<defs>
    <style>
        #background { display: none; }
    </style>
</defs>
<rect id="background" x="0" y="0" width="500" height="500" fill="#e8e437"/>
<!-- beginning of the sketch -->
<g fill="#000" text-anchor="middle"font-size="112">
    <text y="350" x="192">OK</text>
</g>
<!-- end of the sketch -->
</svg>

---

bash script

#!/bin/bash


BASE_DIR=$( cd "$( dirname "${BASH_SOURCE[0]}" )" >/dev/null && pwd )
SVG_DIR="$BASE_DIR/import"
PNG_DIR="$BASE_DIR/export"

for f in `ls $SVG_DIR/*.svg`
do
    g="$PNG_DIR/$(basename "$f" .svg).png"
    BGCOLOR=`grep 'id="background"' $f \
        | sed 's/.* fill="\([^"]*\)".*/\1/'`

    convert $f -transparent "$BGCOLOR" $g
done