How to replace all string between second and third occurance of pipe character using regex?

问题

I would like to replace all the characters occurring between second and third pipe character. Example:

|hello|welcome,to|

In this I want replace welcome,to with a blank value, with a huge file to be replaced. I need a regex pattern to be used in notepad++.

回答1:

Assuming you're parsing each line, i.e. a token cannot include a newline:

Find what:

^((?:[^|\n]*\|){2})[^|\n]*+\|

Replace with:

$1|

Description

• ^- matches the start of line
• ((?:[^|\n]*\|){2}) - matches and captures in group 1:
  • (?:[^|\n]*\|){2} the following expression repeated twice
  • [^|\n]* - any character except a pipe or a newline
  • \| - followed by a pipe
• [^|\n]*+ - the token you want to remove (any char except pipe or newline)
• \| - followed by a pipe

回答2:

In notepad++ use this regex for search:

^([^|]*\|[^|]*\|)[^|]*

And replace by:

$1

([^|]*\|[^|]*\|) matches and captures text before 2nd | into a capturing group #1.

RegEx Demo

来源：https://stackoverflow.com/questions/40067431/how-to-replace-all-string-between-second-and-third-occurance-of-pipe-character-u