How to count the rows which contains non zero values in sql

问题

SELECT round(COUNT(dmd_1wk),2) AS NBR_ITEMS_1WK
  FROM table;

Field dmd_1wk has so many zeros in it. How do I Count the non zero values?

回答1:

Methinks bluefeets answer is probably what you are really looking for, as it sounds like you just want to count non-zeros; but this will get you a count of zero and non-zero items if that's not the case:

SELECT 
  ROUND(SUM(CASE NVL(dmd_1wk, 0) = 0 THEN 1 ELSE 0 END), 2) AS "Zeros",
  ROUND(SUM(CASE NVL(dmd_1wk, 0) != 0 THEN 1 ELSE 0 END), 2) AS "NonZeros"
FROM table

Although there is no point in rounding a whole number, I've included your original ROUNDs as I'm guessing you're using it for formatting, but you might want to use:

TO_CHAR(SUM(...), '999.00')

as that's the intended function for formatting numbers.

回答2:

It sounds like you just need to add a WHERE clause:

SELECT 
      round(COUNT(dmd_1wk),2) AS NBR_ITEMS_1WK
FROM table
WHERE dmd_1wk <> 0;

If you want the count of both non-zero and zero values, then you can use something like:

SELECT 
   round(COUNT(case when dmd_1wk <> 0 then dmd_1wk end),2) AS NBR_ITEMS_1WK_NonZero,
   round(COUNT(case when dmd_1wk = 0 then dmd_1wk end),2) AS NBR_ITEMS_1WK_Zero
FROM table;

回答3:

Method 1: Case Statement. This may be useful if you need to continue to process all rows (which a where clause would prevent).

 SELECT count(case when dmd_1wk = 0 then 0 else 1 end) as NonZeroCount FROM MyTable

Method 2: Where Clause.

 SELECT
   count(1) as NonZeroCount
 FROM
   MyTable
 WHERE
  dmd_1wk <> 0

回答4:

I'd like to offer another solution using NULLIF since COUNT won't count NULL values:

SELECT round(COUNT(NULLIF(dmd_1wk,0)),2) AS NBR_ITEMS_1WK
FROM table;

And here is the Fiddle.

Good luck.

回答5:

You can filter them.

SELECT round(COUNT(dmd_1wk),2) AS NBR_ITEMS_1WK
FROM table
WHERE dmd_1wk <> 0;

来源：https://stackoverflow.com/questions/14814137/how-to-count-the-rows-which-contains-non-zero-values-in-sql

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sql

Oracle

oracle11g