invalid types 'int[int]' for array subscript

问题

This code throws up the compile error given in the title, can anyone tell me what to change?

#include <iostream>

using namespace std;

int main(){

    int myArray[10][10][10];

    for (int i = 0; i <= 9; ++i){
        for (int t = 0; t <=9; ++t){            
            for (int x = 0; x <= 9; ++x){
                for (int y = 0; y <= 9; ++y){

                myArray[i][t][x][y] = i+t+x+y; //This will give each element a value

                      }
                      }
                      }
                      }

    for (int i = 0; i <= 9; ++i){
        for (int t = 0; t <=9; ++t){
            for (int x = 0; x <= 9; ++x){
                for (int y = 0; y <= 9; ++y){

                cout << myArray[i][t][x][y] << endl;

                    }
                    }
                    }                
                    }

    system("pause");

}

thanks in advance

回答1:

You are subscripting a three-dimensional array myArray[10][10][10] four times myArray[i][t][x][y]. You will probably need to add another dimension to your array. Also consider a container like Boost.MultiArray, though that's probably over your head at this point.

回答2:

What to change? Aside from the 3 or 4 dimensional array problem, you should get rid of the magic numbers (10 and 9).

const int DIM_SIZE = 10;
int myArray[DIM_SIZE][DIM_SIZE][DIM_SIZE];

for (int i = 0; i < DIM_SIZE; ++i){
    for (int t = 0; t < DIM_SIZE; ++t){            
        for (int x = 0; x < DIM_SIZE; ++x){

回答3:

int myArray[10][10][10];

should be

int myArray[10][10][10][10];

回答4:

You're trying to access a 3 dimensional array with 4 de-references

You only need 3 loops instead of 4, or int myArray[10][10][10][10];

回答5:

Just for completeness, this error can happen also in a different situation: when you declare an array in an outer scope, but declare another variable with the same name in an inner scope, shadowing the array. Then, when you try to index the array, you are actually accessing the variable in the inner scope, which might not even be an array, or it might be an array with fewer dimensions.

Example:

int a[10];  // a global scope

void f(int a)   // a declared in local scope, overshadows a in global scope
{
  printf("%d", a[0]);  // you trying to access the array a, but actually addressing local argument a
}

回答6:

I think that you had intialized a 3d array but you are trying to access an array with 4 dimension.

来源：https://stackoverflow.com/questions/363864/invalid-types-intint-for-array-subscript