How to ref a TextInput from one screen in another screen in Kivy/Python?

狂风中的少年 提交于 2021-01-29 18:41:03

问题


I'm trying to make an app that can calculate the volume of a cone(so far). I have a screen named ConeVolumeScreen that has two TextInput widgets.

<ConeVolumeScreen>:
    BoxLayout:
        orientation: ...
        padding: ...
        spacing: ...
        Label:
            text: 'Radius:'
        TextInput:
            id: cone_vol_radius
            multiline: False
            input_type: 'number'
        Label:
            text: 'Height:'
        TextInput:
            id: cone_vol_height
            multiline: False
            input_type: 'number'
        Button:
            text: 'Solve'
            on_release: app.root.changeScreen('solve cone volume')               

A person is supposed to enter the radius and height of the cone into these two widgets. Then the person can click on a button to go to the next screen named SolveConeVolumeScreen. In this screen there is a Label that should print the volume of the cone that the person specified.

<SolveConeVolumeScreen>:
    BoxLayout:
        orientation: ...
        padding: ...
        spacing: ...
        Label:
            text: app.getConeVolume(cone_vol_radius, cone_vol_height)

getConeVolume() is a method over here

class CalculatorRoot(BoxLayout):
    def __init__(self, **kwargs):
        super(CalculatorRoot, self).__init__(**kwargs)
        self.screen_list = []

    def changeScreen(self, next_screen):
        if self.ids.calc_screen_manager.current not in self.screen_list:
            self.screen_list.append(self.ids.calc_screen_manager.current)

        if next_screen == 'volume':
            self.ids.calc_screen_manager.current = 'volume_screen'
        elif next_screen == 'area_screen':
            self.ids.calc_screen_manager.current = 'area_screen'
        elif next_screen == 'surface area':
            self.ids.calc_screen_manager.current = 'surfarea_screen'
        elif next_screen == 'cone volume':
            self.ids.calc_screen_manager.current = 'coneVolume_screen'
        elif next_screen == 'solve cone volume':
            self.ids.calc_screen_manager.current = 'solveConeVolume_screen'
        elif next_screen == 'rectangular based pyramid volume':
            self.ids.calc_screen_manager.current = 'rectPyramidVolume_screen'

    def onBackButton(self):
        if self.screen_list:
            self.ids.calc_screen_manager.current = self.screen_list.pop()
            return True
        return False



class CalculatorApp(App):
    def __init__(self, **kwargs):
        super(CalculatorApp, self).__init__(**kwargs)
        Window.bind(on_keyboard=self.onBackButton)

    def onBackButton(self, window, key, *args):
        if key == 27:
            return self.root.onBackButton()

    def build(self):
        return CalculatorRoot()

    def getConeVolume(self, r, h):
        first_step = 'π * ' + str(r) + '^2 * ' + str(h) + ' / 3\n'
        rr = round(r * r, 2)
        second_step = 'π * ' + str(rr) + ' * ' + str(h) + ' / 3\n'
        rh = round(rr * h, 2)
        third_step = 'π * ' + str(rh) + ' / 3\n'
        pirh = round(pi * rh, 2)
        fourth_step = str(pirh) + ' / 3\n'
        result = round(pi * rh, 2)
        final_step = 'The answer is ' + str(result) + '.'
        thing = first_step + second_step + third_step + fourth_step + final_step
        return thing

But the error says that cone_vol_radius is not defined.

 ...
 128:        spacing: min(root.width, root.height) * .02
 129:        Label:

130: text: app.getConeVolume(cone_vol_radius, cone_vol_height) 131: 132:: ... BuilderException: Parser: File "/Users/fayzulloh/Desktop/Calculator App/calculator.kv", line 130: ... 128: spacing: min(root.width, root.height) * .02 129: Label: 130: text: app.getConeVolume(cone_vol_radius, cone_vol_height) 131: 132:: ... NameError: name 'cone_vol_radius' is not defined

please help. I would really appreciate any advice.

here is my screenmanager

<CalculatorRoot>:
    orientation: "vertical"

    ScreenManager:
        id: calc_screen_manager
        StartScreen:
            name: 'start_screen'
        VolumeScreen:
            id: volume_screen
            name: 'volume_screen'
        AreaScreen:
            id: area_screen
            name: 'area_screen'
        SurfaceAreaScreen:
            id: surfarea_screen
            name: 'surfarea_screen'
        ConeVolumeScreen:
            id: coneVolume_screen
            name: 'coneVolume_screen'
        SolveConeVolumeScreen:
            id: solveConeVolume_screen
            name: 'solveConeVolume_screen'
        RectPyramidVolumeScreen:
            id: rectPyramidVolume_screen
            name: 'rectPyramidVolume_screen'

回答1:


Errors

There are a couple of errors in the application.

NameError - Solution

Add root.ids.ids.coneVolume_screen.ids. to the arguments.

AttributeError

After solving the NameError, an AttributeError will occurred. AttributeError: 'NoneType' object has no attribute 'ids'. This is because inner ids are not available yet.

Kivy Language » ids

Note that the outermost widget applies the kv rules to all its inner widgets before any other rules are applied. This means if an inner widget contains ids, these ids may not be available during the inner widget’s __init__ function.

AttributeError: ids - Solutions

  1. Give an id to the Label e.g. id: result
  2. Add an on_pre_enter event to invoke getConeVolume() method.
  3. Replace TextInput object with TextInput's text i.e. replace cone_vol_radius and cone_vol_height with cone_vol_radius.text and cone_vol_height.text respectively.
  4. Add int() function to convert TextInput's text/string to integer.

Snippet

<SolveConeVolumeScreen>:
    on_pre_enter:
        root.ids.result.text = app.getConeVolume(int(app.root.ids.coneVolume_screen.ids.cone_vol_radius.text), int(app.root.ids.coneVolume_screen.ids.cone_vol_height.text))

    BoxLayout:
        orientation: 'vertical'
        Label:
            id: result

Output



来源:https://stackoverflow.com/questions/52152053/how-to-ref-a-textinput-from-one-screen-in-another-screen-in-kivy-python

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