Bash if block syntax

问题

I'm having a syntax error with this if block and can't I haven't been able to correct it

if [[ $X >= 100] || [$Y >= 100 ]]
then
   echo "..."
fi

I've rewrote this, but haven't had any luck on finding the correct syntax. Thanks in advance!

回答1:

This is a syntax error, you should try :

if ((X >= 100 || Y >= 100 ))
then
   echo "..."
fi

NOTE

• with this syntax, no need to remember -ge and such. This is just like arithmetic
• ((...)) is an arithmetic command, which returns an exit status of 0 if the expression is nonzero, or 1 if the expression is zero. Also used as a synonym for let, if side effects (assignments) are needed. See http://mywiki.wooledge.org/ArithmeticExpression

回答2:

What you're looking for is this :

if [[ $X -ge 100 || $Y -ge 100 ]];
then
   echo "..."
fi

回答3:

Your if is fine. Your [[ command is screwed up.

if [[ $X -ge 100 || $Y -ge 100 ]]

回答4:

You seem to be trying to nest [...] expressions, which is not something you can do in bash. The [[ ... ]] expression is an entirely separate construct available in bash. I won't bother posting a correct expression, as the other answers have that well covered.

来源：https://stackoverflow.com/questions/14328606/bash-if-block-syntax