ScopedTypeVariables fail to work with nested where-clauses?

问题

It's a horribly contrived example, but anyway... this typechecks:

newtype Foo c = Foo { runFoo :: c -> Bool }
newtype Bar c = Bar { runBar :: Int -> c }

foo :: Eq c => Bar c -> (c -> [c]) -> Bar (Foo c)
foo bar f = Bar res
 where res n = Foo judge
        where judge c = (c`elem`) . f $ runBar bar n

and works

GHCi> let foo0 = foo (Bar id) (\n -> [n, n*2])
GHCi> map (runFoo $ runBar foo0 4) [1..10]
[False,False,False,True,False,False,False,True,False,False]

but if I add the obvious type signature to the local function judge,

foo :: Eq c => Bar c -> (c -> [c]) -> Bar (Foo c)
foo bar f = Bar res
 where res n = Foo judge
        where judge :: c -> Bool
              judge c = (c`elem`) . f $ runBar bar n

it fails with

Could not deduce (c ~ c2)
from the context (Eq c)
  bound by the type signature for
             foo :: Eq c => Bar c -> (c -> [c]) -> Bar (Foo c)

and so on. Hardly surprising in Haskell 98, but I'd think ScopedTypeVariables should allow to write such signatures, but apparently it doesn't. Is there a specific reason for this, is it intentional that it doesn't work with nested wheres, and what workarounds are there if this turns up in a comparable real-word problem?

回答1:

Apparently you forgot to bring the type variable c into scope with an explicit forall,

{-# LANGUAGE ScopedTypeVariables #-}
module Foobar where

newtype Foo c = Foo { runFoo :: c -> Bool }
newtype Bar c = Bar { runBar :: Int -> c }

foo :: forall c. Eq c => Bar c -> (c -> [c]) -> Bar (Foo c)
foo bar f = Bar res
 where res n = Foo judge
        where judge :: c -> Bool
              judge c = (c`elem`) . f $ runBar bar n

compiles fine.

ScopedTypeVariables by itself doesn't bring the type variables from the signature into scope, only those with an explicit forall are brought into scope.

来源：https://stackoverflow.com/questions/12176037/scopedtypevariables-fail-to-work-with-nested-where-clauses

标签

haskell

type-variables