您如何计算字符串中字符串（实际上是字符）的出现？

问题：

I am doing something where I realised I wanted to count how many / s I could find in a string, and then it struck me, that there were several ways to do it, but couldn't decide on what the best (or easiest) was. 我正在做某件事，我意识到我想计算一个字符串中可以找到多少个/秒，然后让我感到震惊的是，有几种方法可以做到，但无法决定最好的（或最简单的）是。

At the moment I'm going with something like: 目前，我正在处理类似：

string source = "/once/upon/a/time/";
int count = source.Length - source.Replace("/", "").Length;

But I don't like it at all, any takers? 但是，我一点都不喜欢它，对吗？

I don't really want to dig out RegEx for this, do I? 我真的不想为此挖掘RegEx ，对吗？

I know my string is going to have the term I'm searching for, so you can assume that... 我知道我的字符串将包含我要搜索的术语，因此可以假定...

Of course for strings where length > 1 , 当然，对于其中的字符串长度> 1，

string haystack = "/once/upon/a/time";
string needle = "/";
int needleCount = ( haystack.Length - haystack.Replace(needle,"").Length ) / needle.Length;

---

解决方案：

参考一： https://stackoom.com/question/2GzC/您如何计算字符串中字符串-实际上是字符-的出现
参考二： https://oldbug.net/q/2GzC/How-would-you-count-occurrences-of-a-string-actually-a-char-within-a-string

来源：oschina

链接：https://my.oschina.net/u/3797416/blog/4326493