Quering in Database sqlite3

问题

I try to write function for my project, which allows user partial search and highlights rows/records according to column "name" with sqlite3 statements. But I dont know how to wrie the function that it works with SQLite3 statement and matches rows/records in treeview.

def saerch_medicine():
 #query with sqlite3
    conn = sqlite3.connect("pharmacy.db")
    cur = conn.cursor()
    conn.commit()
    cur.execute("SELECT name FROM medicine WHERE name LIKE '%"name_column"%'")
   selections=[] 
     for i in cur:
         tree. selections[0] 
    conn.close()

bt6 = Button(root,text="Serach according column name",width=10,command=saerch)
bt6.grid(row=11,column=1,pady=10,padx=20)
e6 = Entry(root,width=20)
e6.grid(row=11,column=3,pady=10,padx=20)

回答1:

Assume the first column in the tree is the name column, then modify saerch_medicine() (should saerch be search instead?) as below:

def saerch_medicine():
    srch_name = e6.get().strip()
    if srch_name:
        conn = sqlite3.connect("pharmacy.db")
        cur = conn.cursor()
        cur.execute('SELECT name FROM medicine WHERE name LIKE "%{}%"'.format(srch_name))
        matched = [rec[0] for rec in cur]
        conn.close()
        items = [row for row in tree.get_children() if tree.item(row, 'values')[0] in matched]
        tree.selection_set(items)

However if all the records have been inserted into tree, I think you can search the tree directly:

def saerch_medicine():
    srch_name = e6.get().strip()
    if srch_name:
        rows = [row for row in tree.get_children() if srch_name in tree.item(row, 'values')[0]]
        tree.selection_set(rows)

来源：https://stackoverflow.com/questions/63061035/quering-in-database-sqlite3