PHP GuzzleHttp. How to make a post request with params?

问题

How to make a post request with GuzzleHttp( version 5.0 ).

I am trying to do the following:

$client = new \GuzzleHttp\Client();
$client->post(
    'http://www.example.com/user/create',
    array(
        'email' => 'test@gmail.com',
        'name' => 'Test user',
        'password' => 'testpassword'
    )
);

But I am getting the error:

PHP Fatal error: Uncaught exception 'InvalidArgumentException' with the message 'No method can handle the email config key'

回答1:

Try this

$client = new \GuzzleHttp\Client();
$client->post(
    'http://www.example.com/user/create',
    array(
        'form_params' => array(
            'email' => 'test@gmail.com',
            'name' => 'Test user',
            'password' => 'testpassword'
        )
    )
);

回答2:

Since Marco's answer is deprecated, you must use the following syntax (according jasonlfunk's comment) :

$client = new \GuzzleHttp\Client();
$response = $client->request('POST', 'http://www.example.com/user/create', [
    'form_params' => [
        'email' => 'test@gmail.com',
        'name' => 'Test user',
        'password' => 'testpassword',
    ]
]);

Request with POST files

$response = $client->request('POST', 'http://www.example.com/files/post', [
    'multipart' => [
        [
            'name'     => 'file_name',
            'contents' => fopen('/path/to/file', 'r')
        ],
        [
            'name'     => 'csv_header',
            'contents' => 'First Name, Last Name, Username',
            'filename' => 'csv_header.csv'
        ]
    ]
]);

REST verbs usage with params

// PUT
$client->put('http://www.example.com/user/4', [
    'body' => [
        'email' => 'test@gmail.com',
        'name' => 'Test user',
        'password' => 'testpassword',
    ],
    'timeout' => 5
]);

// DELETE
$client->delete('http://www.example.com/user');

Async POST data

Usefull for long server operations.

$client = new \GuzzleHttp\Client();
$promise = $client->requestAsync('POST', 'http://www.example.com/user/create', [
    'form_params' => [
        'email' => 'test@gmail.com',
        'name' => 'Test user',
        'password' => 'testpassword',
    ]
]);
$promise->then(
    function (ResponseInterface $res) {
        echo $res->getStatusCode() . "\n";
    },
    function (RequestException $e) {
        echo $e->getMessage() . "\n";
        echo $e->getRequest()->getMethod();
    }
);

More information for debugging

If you want more details information, you can use debug option like this :

$client = new \GuzzleHttp\Client();
$response = $client->request('POST', 'http://www.example.com/user/create', [
    'form_params' => [
        'email' => 'test@gmail.com',
        'name' => 'Test user',
        'password' => 'testpassword',
    ],
    // If you want more informations during request
    'debug' => true
]);

Documentation is more explicits about new possibilities.

回答3:

Note in Guzzle V6.0+, another source of getting the following error may be incorrect use of JSON as an array:

Passing in the "body" request option as an array to send a POST request has been deprecated. Please use the "form_params" request option to send a application/x-www-form-urlencoded request, or a the "multipart" request option to send a multipart/form-data request.

Incorrect:

$response = $client->post('http://example.com/api', [
    'body' => [
        'name' => 'Example name',
    ]
])

Correct:

$response = $client->post('http://example.com/api', [
    'json' => [
        'name' => 'Example name',
    ]
])

Correct:

$response = $client->post('http://example.com/api', [
    'headers' => ['Content-Type' => 'application/json'],
    'body' => json_encode([
        'name' => 'Example name',
    ])
])

回答4:

$client = new \GuzzleHttp\Client();
$request = $client->post('http://demo.website.com/api', [
    'body' => json_encode($dataArray)
]);
$response = $request->getBody();

Add

openssl.cafile in php.ini file

来源：https://stackoverflow.com/questions/27825667/php-guzzlehttp-how-to-make-a-post-request-with-params