How to convert a json response into yaml in bash

强颜欢笑 提交于 2020-04-10 18:41:09

问题


I read data from a json file with jq. I wanna append the results into a yaml file, but I dont get it working. I am quite new to shell programming. My goal is to append that "users" to an existing "users"-Array in a yaml file.

This is my json file:

#$DEFAULTS_FILE

{"users":
  [
    {"name":"pi",
      "gecos": "Hypriot Pirate",
      "sudo":"ALL=(ALL) NOPASSWD:ALL",
      "shell": "/bin/bash",
      "groups":"users,docker,video",
      "plain_text_passwd":"pi",
      "lock_passwd":"false",
      "ssh_pwauth":"true",
      "chpasswd": {"expire": false}
    },
    {"name":"admin",
      "gecos": "Hypriot Pirate",
      "sudo":"ALL=(ALL) NOPASSWD:ALL",
      "shell": "/bin/bash",
      "primary-group": "users",
      "groups":"users,docker,adm,dialout,audio,plugdev,netdev,video",
      "ssh-import-id":"None",
      "plain_text_passwd":"pi",
      "lock_passwd":"true",
      "ssh_pwauth":"true",
      "chpasswd": "{expire: false}",
      "ssh-authorized-keys": ["ssh-rsa abcdefg1234567890 YOUR_KEY@YOURHOST.local"]
    }
  ]
  }

I filter it with that:

cat $DEFAULTS_FILE | jq .users

I have no clue how to convert that json into a yaml.

My expected result should be:

users:
  - name:                pi
    gecos:               "Hypriot Pirate"
    sudo:                ALL=(ALL) NOPASSWD:ALL
    shell:               /bin/bash
    groups:              users,docker,video
    plain_text_passwd:   pi
    lock_passwd:         false
    ssh_pwauth:          true
    chpasswd: { expire:  false }
  - name:                admin
    primary-group:       users
    shell:               /bin/bash
    sudo:                ALL=(ALL) NOPASSWD:ALL
    groups:              users,docker,adm,dialout,audio,plugdev,netdev,video
    ssh-import-id:       None

I tried to use a second tool called yq which is similar to jq and can write yaml files. But I have no positive progress.

EDIT

I know that I can add content to the yaml with that:

yq w -i "my.yml" "users[+]" "some content"

But I dont know how to merge my json into that.

Any help or hint would be nice, thank you in advance...


回答1:


I'm not sure what rules you're using to get to your expected result. It seems like you're randomly applying different rules to how the values are being converted.

As I understand it, scalar values are just output as is (with potential encoding), objects are output as key/value pairs, and array objects are output with a - for every item. The indentation associates what's part of what.

So based on those rules if you're going to use jq:

def yamlify:
    (objects | to_entries[] | (.value | type) as $type |
        if $type == "array" then
            "\(.key):", (.value | yamlify)
        elif $type == "object" then
            "\(.key):", "    \(.value | yamlify)"
        else
            "\(.key):\t\(.value)"
        end
    )
    // (arrays | select(length > 0)[] | [yamlify] |
        "  - \(.[0])", "    \(.[1:][])"
    )
    // .
    ;

Then to use it, add it to your .jq file and use it:

$ jq -r yamlify input.json
users:
  - name:       pi
    gecos:      Hypriot Pirate
    sudo:       ALL=(ALL) NOPASSWD:ALL
    shell:      /bin/bash
    groups:     users,docker,video
    plain_text_passwd:  pi
    lock_passwd:        false
    ssh_pwauth: true
    chpasswd:
        expire: false
  - name:       admin
    gecos:      Hypriot Pirate
    sudo:       ALL=(ALL) NOPASSWD:ALL
    shell:      /bin/bash
    primary-group:      users
    groups:     users,docker,adm,dialout,audio,plugdev,netdev,video
    ssh-import-id:      None
    plain_text_passwd:  pi
    lock_passwd:        true
    ssh_pwauth: true
    chpasswd:   {expire: false}
    ssh-authorized-keys:
      - ssh-rsa abcdefg1234567890 YOUR_KEY@YOURHOST.local

Here's another variation that aligns the values

def yamlify2:
    (objects | to_entries | (map(.key | length) | max + 2) as $w |
        .[] | (.value | type) as $type |
        if $type == "array" then
            "\(.key):", (.value | yamlify2)
        elif $type == "object" then
            "\(.key):", "    \(.value | yamlify2)"
        else
            "\(.key):\(" " * (.key | $w - length))\(.value)"
        end
    )
    // (arrays | select(length > 0)[] | [yamlify2] |
        "  - \(.[0])", "    \(.[1:][])"
    )
    // .
    ;
$ jq -r yamlify2 input.json
users:
  - name:               pi
    gecos:              Hypriot Pirate
    sudo:               ALL=(ALL) NOPASSWD:ALL
    shell:              /bin/bash
    groups:             users,docker,video
    plain_text_passwd:  pi
    lock_passwd:        false
    ssh_pwauth:         true
    chpasswd:
        expire:  false
  - name:                 admin
    gecos:                Hypriot Pirate
    sudo:                 ALL=(ALL) NOPASSWD:ALL
    shell:                /bin/bash
    primary-group:        users
    groups:               users,docker,adm,dialout,audio,plugdev,netdev,video
    ssh-import-id:        None
    plain_text_passwd:    pi
    lock_passwd:          true
    ssh_pwauth:           true
    chpasswd:             {expire: false}
    ssh-authorized-keys:
      - ssh-rsa abcdefg1234567890 YOUR_KEY@YOURHOST.local



回答2:


I've used ruby to write my json content into yaml.

As for your example, it can be achieved like this:

cat $DEFAULTS_FILE | jq .users | ruby -ryaml -rjson -e 'puts YAML.dump(JSON.parse(STDIN.read))' > my.yml



回答3:


function yaml_validate {
  python -c 'import sys, yaml, json; yaml.safe_load(sys.stdin.read())'
}

function yaml2json {
  python -c 'import sys, yaml, json; print(json.dumps(yaml.safe_load(sys.stdin.read())))'
}

function yaml2json_pretty {
  python -c 'import sys, yaml, json; print(json.dumps(yaml.safe_load(sys.stdin.read()), indent=2, sort_keys=False))'
}

function json_validate {
  python -c 'import sys, yaml, json; json.loads(sys.stdin.read())'
}

function json2yaml {
  python -c 'import sys, yaml, json; print(yaml.dump(json.loads(sys.stdin.read())))'
}

More Bash tricks at http://github.com/frgomes/bash-scripts




回答4:


Another oneliner:

python -c 'import yaml, sys; print(yaml.dump(yaml.load(open(sys.argv[1])), default_flow_style=False))' input.json

(exploiting the fact that valid json is also valid yaml)

And yaml to json:

python -c 'import yaml, json, sys; print(json.dumps(yaml.load(open(sys.argv[1])), indent=2))' input.yaml



回答5:


I'v been able to get the result using the following command:

jq -r .users defaultsfile.txt >> users.yaml

The output is in clear yaml format.



来源:https://stackoverflow.com/questions/53315791/how-to-convert-a-json-response-into-yaml-in-bash

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