快排
procedure qsort(l,r:longint); var i,j,t,m:longint; begin i:=l; j:=r; m:=a[(i+j) div 2]; repeat while a[i]<m do inc(i); while m<a[j] do dec(j); if i<=j then begin t:=a[i]; a[i]:=a[j]; a[j]:=t; inc(i); dec(j); end; until i>j; if i<r then qsort(i,r); if j>l then qsort(l,j); end;
堆
1.数组开两倍
procedure insert(x:longint);
var t,s,v:longint;
begin
len:=len+1; f[len]:=x; s:=len;
while (s<>1)and(f[s div 2]>f[s]) do
begin
v:=f[s div 2]; f[s div 2]:=f[s]; f[s]:=v;
s:=s div 2;
end;
end;
function get:longint;
var t,s,v:longint;
begin
get:=f[1]; f[1]:=f[len]; len:=len-1; t:=1;
while (t*2<=len)or(t*2+1<=len) do
begin
if (t*2+1>len)or(f[t*2]<f[t*2+1])
then s:=t*2 else s:=t*2+1;
if f[t]>f[s] then
begin
v:=f[t]; f[t]:=f[s]; f[s]:=v; t:=s;
end
else break;
end;
end;
欧拉函数(单个数值)
function phi(x:longint):longint; var ans,i:longint; begin ans:=x; for i:=2 to trunc(sqrt(x)) do begin if x mod i=0 then ans:=ans div i*(i-1); while x mod i=0 do x:=x div i; end; if x<>1 then ans:=ans div x*(x-1); exit(ans); end;
欧拉函数(批量处理)
procedure work;
var i,j:longint;
begin
p:=0;
for i:=0 to n do e[i]:=i;
for i:=2 to n do
if e[i]=i then
begin j:=i;
while j<=n do begin e[j]:=e[j] div i*(i-1); inc(j,i); end;
end;
for i:=1 to n do
begin
if e[i]=i-1 then begin inc(p); prime[p]:=i; end;
end;
end;
质数筛法
procedure work(n:longint);
var i,j:longint;
begin
num:=0;
for i:=1 to n do g[i]:=true;
for i:=2 to n do
if g[i]=true then
begin
inc(num); prime[num]:=i;
j:=i*2;
while j<=n do begin g[j]:=false; j:=j+i; end;
end;
end;
质因数分解
procedure fenjie(x:longint);
var i,y:longint;
begin
t:=0;y:=x;
for i:=1 to num do
begin
if prime[i]>y div 2 then exit;
if x mod prime[i]=0 then
begin
inc(t); w[t]:=prime[i];
while x mod prime[i]=0 do x:=x div prime[i];
end;
if x=1 then break;
end;
end;
快速幂
function quick(x,n,p:qword):qword; var ans:qword; begin ans:=1; while n>0 do begin if n and 1>0 then ans:=cheng(ans,x,p); x:=cheng(x,x,p); n:=n>>1; end; exit(ans); end;
快速乘
function cheng(x,n,p:qword):qword;
var ans:qword;
begin
ans:=0;
while n>0 do
begin
if n and 1>0 then ans:=(ans+x) mod p;
x:=(x+x) mod p;
n:=n>>1;
end;
exit(ans);
end;
拓扑排序
for i:=1 to n do if u[i]=0 then begin inc(t); f[t]:=i; end;
repeat
x:=f[t]; dec(t); inc(num);
new(p); p:=a[x];
while p<>nil do
begin
y:=p^.data;
dec(u[y]);
if u[y]=0 then
begin
inc(t); f[t]:=y;
end;
p:=p^.next;
end;
until num=n;
强连通分量tarjan
思路:dfn为遍历到各点的时间,low表示每个点能够追溯到的最早的栈中节点的次序号 instack表示结点是否在栈中。
对图遍历如果x的儿子y没访问过,则访问并用low[y]更行low[x],如果x的儿子y被访问过,则用dfn[y]更新low[x],这样就知道了x最早回溯到的点(在栈中),在栈中low[x]相等的值构成强连通分量。
procedure tarjan(x:longint);
var y:longint; p:point;
begin
inc(s); low[x]:=s; dfn[x]:=s; inc(t); q[t]:=x;
instack[x]:=true;
new(p); p:=a[x];
while p<>nil do
begin
y:=p^.x;
if dfn[y]=0 then begin tarjan(y); low[x]:=min(low[x],low[y]); end
else if instack[y]=true then low[x]:=min(low[x],dfn[y]);
p:=p^.next;
end;
if dfn[x]=low[x] then
begin
inc(num);
repeat
y:=q[t]; dec(t); f[y]:=x;instack[y]:=false;
until x=y;
end;
end;
主程序
for i:=1 to n do begin dfn[i]:=0; low[i]:=0; w[i]:=0; instack[i]:=false; end; s:=0; t:=0; num:=0; for i:=1 to n do if dfn[i]=0 then tarjan(i);
树的直径
思路:求树上最长路,对于各个点,求出它儿子中最长和次长的链相加。
procedure dfs(x,e:longint);
var p:point; y:longint;
begin
s1[x]:=x; s2[x]:=x; new(p); p:=a[x];
while p<>nil do
begin
y:=p^.x;
if y=e then begin p:=p^.next; continue; end;
dfs(y,x);
if f1[y]+p^.v>f1[x] then
begin
f2[x]:=f1[x]; s2[x]:=s1[x];
f1[x]:=f1[y]+p^.v; s1[x]:=y;
end
else
if f1[y]+p^.v>f2[x] then
begin
f2[x]:=f1[y]+p^.v; s2[x]:=y;
end;
p:=p^.next;
end;
if f1[x]+f2[x]>f1[max]+f2[max] then
max:=x;
end;
kmp算法
p[1]:=0; j:=0;
for i:=2 to m do
begin
while (j>0)and(b[j+1]<>b[i]) do j:=p[j];
if b[j+1]=b[i] then inc(j);
p[i]:=j;
end;
j:=0; kmp:=0;
for i:=1 to n do
begin
while (j>0)and(b[j+1]<>a[i]) do j:=p[j];
if b[j+1]=a[i] then inc(j);
if j=m then begin inc(kmp); j:=p[j]; end;
end;
LCA
倍增
1.不要忘记dfs后调用work
2.注意枚举2^i时要包含0,注意顺序
procedure work;
var i,j:longint;
begin
for i:=0 to 19 do
for j:=1 to n do
f[i+1,j]:=f[i,f[i,j]];
end;
function lca(x,y:longint):longint;
var i,t:longint;
begin
if deep[x]<deep[y] then begin t:=x; x:=y; y:=t; end;
for i:=19 downto 0 do
if ((deep[x]-deep[y])>>i)and 1=1 then x:=f[i,x];
if x=y then exit(x);
for i:=19 downto 0 do
if f[i,x]<>f[i,y] then
begin x:=f[i,x]; y:=f[i,y]; end;
exit(f[0,x]);
end;
二分图
染色
function dfs(x,color:longint):boolean;
var p:point; y:longint;
begin
new(p); p:=w[x]; g[x]:=color;
while p<>nil do
begin
y:=p^.x;
if g[y]=color then exit(false);
if (g[y]=0)and(not dfs(y,-color)) then exit(false);
p:=p^.next;
end;
exit(true);
end;
function cheak(s:longint):boolean;
var i:longint;
begin
for i:=1 to n do g[i]:=0;
for i:=1 to n do
if g[i]=0 then
if not dfs(i,1) then exit(false);
exit(true);
end;
组合
费马小定理,快速求C(n,m)的值
procedure make;
var i:longint;
begin
f[0]:=1; g[0]:=1;
for i:=1 to n do
begin
f[i]:=(f[i-1]*i) mod num;
g[i]:=g[i-1]*quick(i,num-2) mod num;
end;
end;
function get(x,y:int64):int64;
var i:longint; t:int64;
begin
if (x=0)or(y=0)or(x=y) then exit(1);
exit(((f[x]*g[x-y]) mod num)*g[y] mod num);
end;
同余
ax≡1(mod m)
program asdf; var a,m,x,y,t:longint; function extgcd(a,b:longint;var x,y:longint):longint; var d:longint; begin if b<>0 then begin d:=extgcd(b,a mod b,y,x); y:=y-(a div b)*x; end else begin x:=1;y:=0; d:=a; end; exit(d); end; begin readln(a,m); x:=0; y:=0; t:=extgcd(a,m,x,y); writeln((x+m) mod m); end.
来源:https://www.cnblogs.com/qtyytq/p/5876625.html