How can I use Guzzle to send a POST request in JSON?

问题

Does anybody know the correct way to post JSON using Guzzle?

$request = $this->client->post(self::URL_REGISTER,array(
                \'content-type\' => \'application/json\'
        ),array(json_encode($_POST)));

I get an internal server error response from the server. It works using Chrome Postman.

回答1:

For Guzzle 5 & 6 you do it like this:

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar']
]);

Docs

回答2:

For Guzzle <= 4:

It's a raw post request so putting the JSON in the body solved the problem

$request = $this->client->post($url,array(
                'content-type' => 'application/json'
        ),array());
$request->setBody($data); #set body!
$response = $request->send();

return $response;

回答3:

The simple and basic way (guzzle6):

$client = new Client([
    'headers' => [ 'Content-Type' => 'application/json' ]
]);

$response = $client->post('http://api.com/CheckItOutNow',
    ['body' => json_encode(
        [
            'hello' => 'World'
        ]
    )]
);

To get the response status code and the content of the body I did this:

echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';

回答4:

This worked for me (using Guzzle 6)

$client = new Client(); 
$result = $client->post('http://api.example.com', [
            'json' => [
                'value_1' => 'number1',
                'Value_group' =>  
                             array("value_2" => "number2",
                                    "value_3" => "number3")
                    ]
                ]);

echo($result->getBody()->getContents());

回答5:

$client = new \GuzzleHttp\Client();

$body['grant_type'] = "client_credentials";
$body['client_id'] = $this->client_id;
$body['client_secret'] = $this->client_secret;

$res = $client->post($url, [ 'body' => json_encode($body) ]);

$code = $res->getStatusCode();
$result = $res->json();

回答6:

This works for me with Guzzle 6.2 :

$gClient =  new \GuzzleHttp\Client(['base_uri' => 'www.foo.bar']);
$res = $gClient->post('ws/endpoint',
                            array(
                                'headers'=>array('Content-Type'=>'application/json'),
                                'json'=>array('someData'=>'xxxxx','moreData'=>'zzzzzzz')
                                )
                    );

According to the documentation guzzle do the json_encode

回答7:

$client = new \GuzzleHttp\Client(['base_uri' => 'http://example.com/api']);

$response = $client->post('/save', [
    'json' => [
        'name' => 'John Doe'
    ]
]);

return $response->getBody();

回答8:

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    'json' => ['foo' => 'bar']
]);

See Docs.

回答9:

The answer from @user3379466 can be made to work by setting $data as follows:

$data = "{'some_key' : 'some_value'}";

What our project needed was to insert a variable into an array inside the json string, which I did as follows (in case this helps anyone):

$data = "{\"collection\" : [$existing_variable]}";

So with $existing_variable being, say, 90210, you get:

echo $data;
//{"collection" : [90210]}

Also worth noting is that you might want to also set the 'Accept' => 'application/json' as well in case the endpoint you're hitting cares about that kind of thing.

回答10:

@user3379466 is correct, but here I rewrite in full:

-package that you need:

 "require": {
    "php"  : ">=5.3.9",
    "guzzlehttp/guzzle": "^3.8"
},

-php code (Digest is a type so pick different type if you need to, i have to include api server for authentication in this paragraph, some does not need to authenticate. If you use json you will need to replace any text 'xml' with 'json' and the data below should be a json string too):

$client = new Client('https://api.yourbaseapiserver.com/incidents.xml', array('version' => 'v1.3', 'request.options' => array('headers' => array('Accept' => 'application/vnd.yourbaseapiserver.v1.1+xml', 'Content-Type' => 'text/xml'), 'auth' => array('username@gmail.com', 'password', 'Digest'),)));

$url          = "https://api.yourbaseapiserver.com/incidents.xml";
        
$data = '<incident>
<name>Incident Title2a</name>
<priority>Medium</priority>
<requester><email>dsss@mail.ca</email></requester>
<description>description2a</description>
</incident>';

    $request = $client->post($url, array('content-type' => 'application/xml',));

    $request->setBody($data); #set body! this is body of request object and not a body field in the header section so don't be confused.

    $response = $request->send(); #you must do send() method!
    echo $response->getBody(); #you should see the response body from the server on success
    die;

--- Solution for * Guzzle 6 * --- -package that you need:

 "require": {
    "php"  : ">=5.5.0",
    "guzzlehttp/guzzle": "~6.0"
},

$client = new Client([
                             // Base URI is used with relative requests
                             'base_uri' => 'https://api.compay.com/',
                             // You can set any number of default request options.
                             'timeout'  => 3.0,
                             'auth'     => array('you@gmail.ca', 'dsfddfdfpassword', 'Digest'),
                             'headers' => array('Accept'        => 'application/vnd.comay.v1.1+xml',
                                                'Content-Type'  => 'text/xml'),
                         ]);

$url = "https://api.compay.com/cases.xml";
    $data string variable is defined same as above.


    // Provide the body as a string.
    $r = $client->request('POST', $url, [
        'body' => $data
    ]);

    echo $r->getBody();
    die;

回答11:

Above answers did not worked for me somehow. But this works fine for me.

 $client = new Client('' . $appUrl['scheme'] . '://' . $appUrl['host'] . '' . $appUrl['path']);

 $request = $client->post($base_url, array('content-type' => 'application/json'), json_encode($appUrl['query']));

回答12:

Simply use this it will work

   $auth = base64_encode('user:'.config('mailchimp.api_key'));
    //API URL
    $urll = "https://".config('mailchimp.data_center').".api.mailchimp.com/3.0/batches";
    //API authentication Header
    $headers = array(
        'Accept'     => 'application/json',
        'Authorization' => 'Basic '.$auth
    );
    $client = new Client();
    $req_Memeber = new Request('POST', $urll, $headers, $userlist);
    // promise
    $promise = $client->sendAsync($req_Memeber)->then(function ($res){
            echo "Synched";
        });
      $promise->wait();

来源：https://stackoverflow.com/questions/22244738/how-can-i-use-guzzle-to-send-a-post-request-in-json

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